Answer:
If nitrogen = 30.4% then oxygen = 100-30.4 = 69.6%
divide each % value by atomic mass
N = 30.4/14 = 2.17
O = 69.6/16 = 4.35
Divide each y smaller:
N = 2.17/2.17 = 1
O = 4.35/2.17 = 2
Explanation:
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Answer:
Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃
Explanation:
The first step is is to find the limiting reactant; you do this using stoichiometry.
The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.
In this problem, SO₂ is the limiting reactant.
Now to find the theoretical yield we will use the smallest value of SO₃.
I have uploaded a picture to better illustrate the problem and hope it helps.
Answer:
A. 7.56
b. 57.12
Explanation:
Hope that's right have a nice day :)
Answer:-
KOH determines how much Mg(OH)2 is made.
2 mol of Mg(OH)2 formed
Explanation:-
The balanced equation is
MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,
From seeing the coefficients we notice
2 mol of KOH reacts with 1 mol of MgCl2
4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2
3 moles of MgCl2 was added but only 2 mol react.
So we see there is excess MgCl2 .
Hence KOH is the limiting reactant.
So KOH determines how much Mg(OH)2 is made.
We see from the balanced chemical equation,
2 mol of KOH gives 1 mol of Mg(OH)2.
4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.
