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zimovet [89]
3 years ago
6

Ice Station Bravo near the North Pole launched a helium-filled balloon to check atmospheric conditions. At sea level (1.0 atm) w

here the balloon was launched, it had a volume of 0.93m^3 . It rose to an altitude of 18000m where the atmospheric pressure dropped to 0.072atm.
What is the volume of the balloon at that altitude assuming that the temperature was the same at sea level?
Chemistry
1 answer:
Reika [66]3 years ago
8 0

Answer:

12.9 m³ is the new volume

Explanation:

As the temperature keeps on constant, and the moles of the gas remains constant too, if we decrease the pressure, the volume will increase.  If the volume is decreased, pressure will be higher.

The relation is this: P₁ . V₁  = P₂  . V₂

1 atm . 0.93m³ = 0.072 atm . V₂

0.93m³ .atm / 0.072 atm = V₂

V₂ = 12.9 m³

In conclusion and as we said, pressure has highly decreased so volume has highly increased.

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Determine whether each molecule given below is polar or nonpolar. of2
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Answer : The molecule OF_2 is a polar molecule.

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Non-polar molecule : When the arrangement of the molecule is symmetrical then the molecule is non-polar.

The given molecule is, OF_2

The electronegativities of oxygen and fluorine are different. The molecular geometry of OF_2 is bent. As, Fluorine is more elctronegative than the oxygen. So, the arrows putting towards the more electronegative element i.e, fluorine. These arrows do not balance each other. Due to this, the asymmetrical arrangement of these bonds makes the molecule polar.

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7 0
3 years ago
In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the perce
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Answer:

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

                  % error = [ 0.79 / 6.11 ] x 100

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Round to the 2 significant figure

% error = 13 %

So, option c is correct            

7 0
4 years ago
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