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Mrrafil [7]
2 years ago
13

A smaller gear driving a larger gear gives a blank advantage (called blank gears) 

Chemistry
1 answer:
charle [14.2K]2 years ago
6 0
Jduddhhdid sewer feeder dad
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Do bases lose or gain hydrogen ions?<br><br><br>Help :-)
kodGreya [7K]

Answer:

Acids are classified in the Bronsted Lowry acid-base theory as species, which losses hydrogen ions (H+, known as protons) in a chemical reaction (and are foundation species that accept hydrogen ions).

7 0
3 years ago
One mole of carbon will have the same number of particles as one mole of hydrogen.
AVprozaik [17]
And the answer is False,it does not have the same number with particles as the one mole of hydrogen.
3 0
3 years ago
Read 2 more answers
A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
3 years ago
The molecule shown is a
Pani-rosa [81]

c is the answer a benzene

8 0
3 years ago
The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.
NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0
3 years ago
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