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koban [17]
3 years ago
5

What is 0.9×10 to the negative power of 1 in standard notation

Mathematics
2 answers:
yanalaym [24]3 years ago
5 0
a^{-1}=\dfrac{1}{a}\\\\0.9\cdot10^{-1}=0.9\cdot\dfrac{1}{10}=\dfrac{0.9}{10}=\dfrac{0.9\cdot10}{10\cdot10}=\dfrac{9}{100}=0.09
andreev551 [17]3 years ago
3 0
0.09 is the answer …

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Outcome
Luda [366]

Answer: sorry the answer is not clear.

Step-by-step explanation:

4 0
3 years ago
What is the conjugate of 1 + √5
RUDIKE [14]

Answer:

Exact Form:

1 + √5

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8 0
3 years ago
Least to greatest -2, -3/4, -0.45, 3%, 0.36
Crank

Answer:

\large\boxed{-2,\ -\dfrac{3}{4},\ -0.45,\ 3\%,\ 0.36}

Step-by-step explanation:

We convert some numbers to decimal fractions:

-2 = -2.00

-3/4 = -0.75

-0.45

3% = 0.03

0.36

We order

-2, -0.75, -0.45, 0.03, 0.36

\dfrac{3}{4}=\dfrac{3\cdot25}{4\cdot25}=\frac{75}{100}=0.75

other method

\dfrac{3}{4}=3:4=0.75        (use a calculator)

p\%=\dfrac{p}{100}\to 3\%=\dfrac{3}{100}=0.03

8 0
3 years ago
Select the basic integration formula you can use to find the indefinite integral.
kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C

Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
3 years ago
Does -2 4/5 + 6 1/3= 2/5
aleksandr82 [10.1K]

Answer:

yes.

Step-by-step explanation:

6 0
3 years ago
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