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Law Incorporation [45]

3 years ago

13

A family is driving 600 miles. Assuming they stop to get gas 3 times and eat 2 times, how many hours will it take them to reach

their destination? How would you estimate the time?

1 answer:

Umnica [9.8K]3 years ago

8 0

Lets assume that they are driving at an average of 70mph, and getting gas takes 10 minutes, and stopping to eat takes 30.

t=d/s

t=600/70
t=8.57

Stopping to eat twice is 30 x 2 = 60 (another hour)

and Gas is 10 x 3 = 30 minutes (0.5 hours)

Total time is,

8.57+1+0.5 =10.07

So the trip will take approx 10.7 hours total.

(This is using my assumptions, from my experience!)

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Assignment: $\bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}$

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Answer: $\boxed{\bold{-14x+8}}$

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$\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}$

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3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

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Answer:

a) $n = 9604$

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.01\sqrt{n} = 1.96*0.5$

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b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

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$\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}$

$n = 380.3$

Rouding up

n = 381

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