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3 years ago

A cubic centimeter is the space taken by a square whose sides are 1 centimeters long true or false

Mathematics

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

False

Step-by-step explanation:

A square has two dimensions (length times width), whereas a cube has three (length times width times height). Therefore, "a cc is the space taken by a cube of side 1 cm."

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Review:

alex41 [277]

Answer:

Step-by-step explanation:

Well 6 to the second power is when you multiply 6 x 6 = 36

And ab= -320

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3 years ago

Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the

Dominik [7]

G=37

Angle ACD and angle DCB are a linear pair. Meaning they are supplementary.

ACD=90 degrees

180-90=90

90 degrees equals the angle of DCB.

90-53=37

So g=37

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3 years ago

The product of 40 and the distance to the finish line

nalin [4]

Answer:

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Step-by-step explanation:

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3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

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3 years ago

Ali wrote this first step in how to add 27 12 on a hundred chart

lina2011 [118]

Say the question more clearly please

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