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vaieri [72.5K]
3 years ago
13

You apply a 150 N push on a frictionless sled over a period of 2 seconds. Show that the sled’s momentum changes by 300 kg·m/s.

Physics
1 answer:
Savatey [412]3 years ago
8 0

Explanation:

Given parameters:

Force applied = 150N

Time  = 2s

Unknown:

Momentum change = ?

Solution:

The momentum change of a body is the difference between its initial and final momentum.

Momentum is the same as the impulse exerted on a body which is the product of force  and time

   Momentum = mass x velocity = force x time

The body initially at rest has a momentum of 0, as the momentum changes;

      Momentum change = Final momentum - initial momentum

                                         = f x t - (0)

                                         = (150 x 2) - 0

     Momentum change = 300kgm/s

Since the body is a frictionless surface, the net force is the same as the applied force.

learn more

Momentum brainly.com/question/9484203

#learnwithBrainly

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A firecracker breaks up into two pieces , one has a mass of 200 g and files off along the x –axis with a speed of 82.0 m/s and t
Readme [11.4K]

Answer:

A) 21.2 kg.m/s at 39.5 degrees from the x-axis

Explanation:

Mass of the smaller piece = 200g = 200/1000 = 0.2 kg

Mass of the bigger piece = 300g = 300/1000 = 0.3 kg

Velocity of the small piece = 82 m/s

Velocity of the bigger piece = 45 m/s

Final momentum of smaller piece = 0.2 × 82 = 16.4 kg.m/s

Final momentum of bigger piece = 0.3 × 45 = 13.5 kg.m/s

since they acted at 90oc to each other (x and y axis) and also momentum is vector quantity; then we can use Pythagoras theorems

Resultant momentum² = 16.4² + 13.5² = 451.21

Resultant momentum = √451.21 = 21.2 kg.m/s at angle 39.5 degrees to the x-axis  ( tan^-1 (13.5 / 16.4)

5 0
3 years ago
José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be remo
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Answer:

179 kg

Explanation:

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3 years ago
a runner runs 2.88 m/s north. she accelerates .350 m/s ^2 at a -52.0 degree angle at the point in the motion where she is runnin
Vitek1552 [10]

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3 years ago
An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the
jok3333 [9.3K]

Answer:

m = 1.5 kg

Explanation:

Data:

  • Aceleration (a) = 8 m/s²
  • Force (F) = 12 N
  • Mass (m) = ?

Use formula:

  • \boxed{m = \frac{F}{a}}

Replace in the formula:

  • \boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}

Equate the newtons:

  • \boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}

Simplify m/s²:

  • \boxed{m = \frac{12kg}{8}}

It divides:

  • \boxed{m =1.5kg}

What is the mass of the train?

The mass of the train is <u>1.5 kilograms.</u>

4 0
3 years ago
A 1400-kg car traveling east at 25m/s collides with a 1800-kg car traveling at a speed of 20m/s in a direction that makes angle
julia-pushkina [17]
M1*V1 + M2*V2 = M1*V + M2*V.
1400*25 + 1800*20[180+40]=1400*V+1800*V.
Divide both sides by 100:
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350 + 360[220o] = 32V.
350 - 276-231i = 32V.
74 - 231i = 32V.
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V = 7.6m/s[-72.2o]=7.6m/s[72o] S. of E.
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