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3 years ago

According the Merriam Webster dictionary the definition of falling is, "to descend freely by the force of gravity".

Physics

1 answer:

ki77a [65]3 years ago

3 0

Answer:

Explained

Explanation:

If you are in a rotating system newton's law do not work .Adding a frictious force can make the law work. If an orbiting object is in constant freefall under gravity . Even elliptical planet orbits are examples of freefall under gravity. The force F which the planet feels; this force can be resolved into two components, centripetal force F_C and tangential force F_T.

The tangential force causes an acceleration(newton's second law) which decreases the speed and the centripetal force causes the velocity to turn. In there is circular orbit of radius R, F_T=0 and the centripetal force is F_C=Mv^2/R;

The centrifugal force would be a vector with magnitude Mv^2/R( same as that of centripetal) pointing away from the sun but it does not really exist.

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The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?

Strike441 [17]

Answer:

Option B. N2(g) + 3H2(g) → 2NH3(g)

Explanation:

When nitrogen react with hydrogen, they form a product as shown below:

N2+ H2 → NH3

We need to balance the equation. This is illustrated below:

There are 2 atoms of nitrogen on the left side and 1 atom on the right side. To balance it, put 2 in front of NH3 as shown below:

N2+ H2 → 2NH3

Now, There are a total of 6 atoms of Hydrogen on the right side and 2 atoms on the left side side. This can be balanced by putting 3 in front of H2 as shown below:

N2+ 3H2 → 2NH3

Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation

4 0

3 years ago

Read 2 more answers

8_murik_8 [283]

Answer: 2.61 s

Explanation:

We are given the following data:

$s=5 ft$ is the initial height of the object

$v=40 ft/s$ is the initial height of the object

In addition, the motion of the object is given by:

$h=-16t^{2}+ vt +s$ (1)

Where:

$h=0 ft$ is the final height of the object

$t$ is the time the object is in the air before hitting the ground

Rewritting (1) with the given data:

$0=-16t^{2}+ 40t +5$ (2)

Solving the quadratic equation with the quadratic formula $t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ , where $a=-16$ , $b=40$ , $c=5$ and choosing the positive value of time:

$t=\frac{-40\pm\sqrt{(-40)^{2}-4(-16)(5)}}{2(-16)}$ (3)

$t=2.61 s$ (4) This is the time

5 0

4 years ago

Which of the following phase changes occurs at point B on the phase diagram shown below? (choose all that apply)

Alex

I’m just gonna try an wander the the best I can, sorry if this is wrong I haven’t been taught this subject yet-

I’m Guessing its sublimating

( I’m sorry if this is wrong, remember I haven’t been taught this yet I’m only in 6th-)

4 0

3 years ago

Read 2 more answers

Newton’s Law of Cooling. Newton’s law of cooling states that the rate of change in the temperature T(t) of a body is proportiona

nexus9112 [7]

Answer:

After 30 minutes, the temperature of the body is: T₁₀ = 311.60 K

After 60 minutes, the temperature of the body is: T₂₀ = 298.18 K

Explanation:

Given that:

$\dfrac{dT}{dt}= K \bigg [ M(t) -T(t)\bigg]$

where;

K = 0.04

M(t) = 293

Then;

$\dfrac{dT}{dt}= 0.04 \bigg [ 293 -T\bigg]$

$\dfrac{dT}{dt}= 11.72 -0.04 \ T$

Using Euler's Formula;

$T_{n+1} = T_n + hf( t_n, T_n)$

where;

$f(t_n,T_n) = 11.72 - 0.04 T_n$

Then;

$T_{n+1} = T_n + 3.0 (11.72-0.04 \ T_n)$

$T_{n+1} = 0.88T_n + 35.16 \ ---(1)$

At initial state $t_0$ (0); $T_0$ = 360

At t₁ = 3.0 when T₀ = 360

$T_1= 0.88 T_o + 35.16$

$T_1= 0.88 (360) + 35.16$

$T_1 = 351.96 \ K$

At t₂ = 6.0 when T₂ = 0.88T₁ + 35.16

T₂ = 0.88(351.96) + 35.16

T₂ = 344.89 K

At t₃ = 9.0 when T₃ = 0.88T₂ + 35.16

T₃ = 0.88(344.89) + 35.16

T₃ =338.66 K

At t₄ = 12.0 when T₄ = 0.88T₃ + 35.16

T₄ = 0.88(338.66) + 35.16

T₄ = 333.18 K

At t₅ = 15.0 when T₅ = 0.88T₄ + 35.16

T₅ = 0.88(333.18) + 35.16

T₅ = 328.36 K

At t₆ = 18.0 when T₆ = 0.88T₅ + 35.16

T₆ = 0.88(328.36) + 35.16

T₆ = 324.12 K

At t₇ = 21.0 when T₇ = 0.88T₆ + 35.16

T₇ = 0.88(324.12) + 35.16

T₇ = 320.39 K

At t₈ = 24.0 when T₈ = 0.88T₇ + 35.16

T₈ = 0.88(320.29) + 35.16

T₈ = 317.02 K

At t₉ = 27.0 when T₉ = 0.88T₈ + 35.16

T₉ = 0.88(317.02) + 35.16

T₉ = 314.14 K

At t₁₀ = 30 when T₁₀ = 0.88T₉ + 35.16

T₁₀ = 0.88(314.14) + 35.16

T₁₀ = 311.60 K

At t₁₁ = 33.0 when T₁₁ = 0.88T₁₀ + 35.16

T₁₁ = 0.88(311.60) + 35.16

T₁₁ = 309.37 K

At t₁₂ = 36.0 when T₁₂ = 0.88T₁₁ + 35.16

T₁₂ = 0.88(309.37)+ 35.16

T₁₂ = 307.41 K

At t₁₃ = 39.0 when T₁₃ = 0.88T₁₂ + 35.16

T₁₃ = 0.88( 307.41) + 35.16

T₁₃ = 305.68 K

At t₁₄ = 42.0 when T₁₄ = 0.88T₁₃ + 35.16

T₁₄ = 0.88(305.68) + 35.16

T₁₄ = 304.16 K

At t₁₅ = 45.0 when T₁₅ = 0.88T₁₄ + 35.16

T₁₅ = 0.88(304.16) + 35.16

T₁₅ = 302.82 K

At t₁₆ = 48.0 when T₁₆ = 0.88T₁₅ + 35.16

T₁₆ = 0.88(302.82) + 35.16

T₁₆ = 301.64 K

At t₁₇ = 51.0 when T₁₇ = 0.88T₁₆ + 35.16

T₁₇ = 0.88(301.64) + 35.16

T₁₇ = 300.60 K

At t₁₈ = 54.0 when T₁₈ = 0.88T₁₇ + 35.16

T₁₈ = 0.88(300.60) + 35.16

T₁₈ = 299.69 K

At t₁₉ = 57.0 when T₁₉ = 0.88T₁₈ + 35.16

T₁₉ = 0.88(299.69) + 35.16

T₁₉ = 298.89 K

At t₂₀ = 60 when T₂₀ = 0.88T₁₉ + 35.16

T₂₀ = 0.88(298.89) + 35.16

T₂₀ = 298.18 K

4 0

3 years ago

Which soap sample most likely took the longest time to dissolve

solniwko [45]

I think A but I’m not positively sure

4 0

4 years ago

Read 2 more answers