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Slav-nsk [51]
3 years ago
5

PLEASE HELP 15 POINTS...PLEASE HELP

Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:

-2/3

Step-by-step explanation:

<u>Rise</u> = <u>-2</u>

Run     3

Semenov [28]3 years ago
5 0

Answer:

-2/3

Step-by-step explanation:

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What is the rate of change of the function?
Alona [7]

We have been given that on a coordinate plane a line with negative slope passes through points (0,1) and (1,-1). We are asked to find the rate of the change of the function.

We know that slope represents rate of change of function.

We will use slope formula to solve our given problem.

m=\frac{y_2-y_1}{x_2-x_1}

Let (x_1,y_1)=(0,1) and (x_2,y_2)=(1,-1).

m=\frac{-1-1}{1-0}

m=\frac{-2}{1}

m=-2

Therefore, the rate of change of the given function is -2.

8 0
3 years ago
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Which statement explains why one of these triangles is a right triangle? HELP ME!!
lesantik [10]

Answer:

Triangle B

Step-by-step explanation: Look at the square figure on one of the corners. That means that your triangle is a right triangle, which means, its measurement on that corner is 90 degrees

7 0
3 years ago
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Which of the following statements are true?
Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is false.

B.  The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is true.

C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

D. The function f(x)=\dfrac{1}{2}\sqrt{x} has the domain and the range all non-negative real values. The function  f(x)=\sqrt[3]{x} has the domain and the range all real values. So this option is false.

3 0
3 years ago
Which expression can be used to determine the average rate of change in f(x) over the interval mc001-1.jpg
Mrac [35]
The average rate of change of a function f(x) over an interval (a, b) is given by
\frac{f(b)-f(a)}{b-a}

Therefore, given a function, f(x), over an interval (2, 9), the average rate of change of the function can be found using the expression
\frac{f(9)-f(2)}{9-2}
8 0
3 years ago
Read 2 more answers
F(x)=-5x+2 and g(x)=1/2x+4 find f(g(12))
skad [1K]

Answer:

- 48

Step-by-step explanation:

If you want to learn more about this concept, it's called composition of functions.

First, you plug in g(x) as if it were x into f(x).

f(g(x))= -5 (1/2x + 4) + 2

= -5/2x - 20 + 2

= -5/2x - 18

Then, plug in the value given, as x.

= -5/2 (12) - 18

= -30 - 18

= - 48

I hope this helped!

3 0
3 years ago
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