The number of combinations will be 6 for even numbers.
<h3>What is the combination?</h3>
The arrangement of the different things or numbers in a number of ways is called the combination.
Given that:-
- A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?
The total sample numbers are from 0 to 5 which are 0,1,2,3,4,5.
The even numbers are 0,2,4.
The combinations will be given by:-
C = 3!
C = 3 x 2 x1
C = 6
Therefore the number of combinations will be 6 for even numbers.
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Answer:
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard = (1/5) hour = 0.20 hour
b) Centimetres of snow that accumulate per hour = 5 cm
Step-by-step explanation:
Complete Question
We can calculate the depth d of snow, in centimeters, that accumulates in Harper's yard during the first h hours of a snowstorm using the equation d=5h.
a) How many hours does it take for 1 centimeter of snow to accumulate in Harper's yard? hours
b) How many centimeters of snow accumulate per hour? centimeters
Solution
The depth of snow, d, in centimetres that accumulates in Harper's yard in h hours is given d = 5h
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard.
d = 5h
d = 1 cm
h = ?
1 = 5h
h = (1/5) = 0.20 hour
b) Centimetres of snow that accumulate per hour.
d = 5h
In 1 hour, h = 1 hour
d = ?
d = 5 × 1 = 5 cm
Hope this Helps!!!
If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.
We are required to find the speed of slower car and faster car.
let the speed of slower car be x mph.
In this way the speed of faster car be (x+20) mph.
Speed=Distance/ time
We have to first take slower car.
x=165/Time
Time=165/x-----------1
Now by taking faster car.
x+20=225/time
Time=225/(x+20)-------2
From equation 1 an equation 2.
165/x=225/(x+20)
225x=165x+3300
225x-165x=3300
60x=3300
x=55 mph
Faster car=55+20
=75 mph.
Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
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Answer:
b
Step-by-step explanation:
Answer:
2x − 5
Step-by-step explanation:
To solve, divide the numerator by the denominator. The result (not including the remainder) will be the equation of the slant asymptote.
We can tell the first term of the quotient will be 2x, so the answer will be either 2x − 5 or 2x − 17/3.
The easiest method here is to simply multiply these by denominator.
(3x² − 1) (2x − 5) = 6x³ − 15x² − 2x + 5
(3x² − 1) (2x − 17/3) = 6x³ − 17x² − 2x + 17/3
So the answer must be 2x − 5.
Alternatively, you can use long division.
