Answer:
79.7°
Step-by-step explanation:
We resolve the speed of the plane into horizontal and vertical components respectively as 300cos75° and 300sin75° respectively. Since the wind blows due west at a speed of 25 miles per hour, its direction is horizontal and is given by 25cos180° = -25 mph. We now add both horizontal components to get the resultant horizontal component of the airplane's speed.
So 300cos75° mph + (-25 mph) = 77.646 - 25 = 52.646 mph.
The vertical component of its speed is 300sin75° since that's the only horizontal motion of the airplane. So the resultant vertical component of the airplane's speed is 300sin75° = 289.778 mph
The direction of the plane, Ф = tan⁻¹(vertical component of speed/horizontal component of speed)
Ф = tan⁻¹(289.778 mph/52.646 mph)
Ф = tan⁻¹(5.5043)
Ф = 79.7°
Answer:
The photo attached could be of use
Step-by-step explanation:
For the answer to the question above,
z=6-(3/4)y-2x
<span>z+(3/4)y+2x=6 </span>
<span>Just by connecting the three points on the graph, I got this equation by isolating each plane to figure it out. This equation only explains the plane bounded by these three points, though, so to draw it just plot the points and connect them.</span>
<u><em>Solution:</em></u>
<u><em></em></u>
Hope this helps!
