1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
joja [24]
3 years ago
10

The partial factorization of x2 – x – 12 is modeled with algebra tiles.Which unit tiles are needed to complete the factorization

?
Mathematics
2 answers:
S_A_V [24]3 years ago
3 0
Please write that as x^2 - x - 12 (the "^" symbol denotes exponentiation).

x^2 - x - 12 factors to (x + 3)(x - 4),  Check this by multiplication:

x^2 + 3x - 4x - 12 = x^2 - x - 12 (OK).
astra-53 [7]3 years ago
3 0

Answer: The unit of tiles that are needed to complete the factorization are

(x-4)(x+3)

Step-by-step explanation:

Since we have given that

x^2-x-12=0

We need to factorise the above quadratic equation:

We use "Split the middle term":

x^2-x-12=0\\\\x^2-4x+3x-12=0\\\\x(x-4)+3(x-4)=0\\\\(x-4)(x+3)=0

Hence, the unit of tiles that are needed to complete the factorization are

(x-4)(x+3)

You might be interested in
25 cm<br> How do you find the area of circle
3241004551 [841]

Answer:

You do pi times radius squared

3 0
3 years ago
Describe how the graphs of square root and cube root functions are similar and how they are different.
Molodets [167]

Answer:

Just as the square root is a number that, when squared, gives the radicand, the cube root is a number that, when cubed, gives the radicand. Cubing a number is the same as taking it to the third power: 23 is 2 cubed, so the cube root of 23 is 2.

Step-by-step explanation:

there i hope you understood

5 0
3 years ago
Read 2 more answers
Can someone help me with this it is for mathh.
lapo4ka [179]

Answer: it would be  P=4n

8 0
2 years ago
HELPPP KE PJEASE. ASAPPPP ITS FOR A QUIZZZ
san4es73 [151]
=(1/2) * 2 * 3.2 + (1/2) *2 * 3.2 + (1/2) * 2 * 4 + (1/2) * 2 * 4
= 2 * 3.2 + 2 * 4
= 2 * (3.2 + 4)
= 2 * 7.2
= 14.4 sq feet
2 * 14.4 = 28.8 sq feet
8 0
3 years ago
Part I - To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nico
IRINA_888 [86]

Answer:

(I) 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

(II) No, since the value 28.4 does not fall in the 98% confidence interval.

Step-by-step explanation:

We are given that a new cigarette has recently been marketed.

The FDA tests on this cigarette gave a mean nicotine content of 27.3 milligrams and standard deviation of 2.8 milligrams for a sample of 9 cigarettes.

Firstly, the Pivotal quantity for 99% confidence interval for the population mean is given by;

                                  P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean nicotine content = 27.3 milligrams

            s = sample standard deviation = 2.8 milligrams

            n = sample of cigarettes = 9

            \mu = true mean nicotine content

<em>Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>Part I</u> : So, 99% confidence interval for the population mean, \mu is ;

P(-3.355 < t_8 < 3.355) = 0.99  {As the critical value of t at 8 degree

                                      of freedom are -3.355 & 3.355 with P = 0.5%}  

P(-3.355 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 3.355) = 0.99

P( -3.355 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 3.355 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X-3.355 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+3.355 \times {\frac{s}{\sqrt{n} } } ) = 0.99

<u />

<u>99% confidence interval for</u> \mu = [ \bar X-3.355 \times {\frac{s}{\sqrt{n} } } , \bar X+3.355 \times {\frac{s}{\sqrt{n} } } ]

                                          = [ 27.3-3.355 \times {\frac{2.8}{\sqrt{9} } } , 27.3+3.355 \times {\frac{2.8}{\sqrt{9} } } ]

                                          = [27.3 \pm 3.131]

                                          = [24.169 mg , 30.431 mg]

Therefore, 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

<u>Part II</u> : We are given that the FDA tests on this cigarette gave a mean nicotine content of 24.9 milligrams and standard deviation of 2.6 milligrams for a sample of n = 9 cigarettes.

The FDA claims that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette, and their stated reliability is 98%.

The Pivotal quantity for 98% confidence interval for the population mean is given by;

                                  P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean nicotine content = 24.9 milligrams

            s = sample standard deviation = 2.6 milligrams

            n = sample of cigarettes = 9

            \mu = true mean nicotine content

<em>Here for constructing 98% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

So, 98% confidence interval for the population mean, \mu is ;

P(-2.896 < t_8 < 2.896) = 0.98  {As the critical value of t at 8 degree

                                       of freedom are -2.896 & 2.896 with P = 1%}  

P(-2.896 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.896) = 0.98

P( -2.896 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.896 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.896 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.896 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u />

<u>98% confidence interval for</u> \mu = [ \bar X-2.896 \times {\frac{s}{\sqrt{n} } } , \bar X+2.896 \times {\frac{s}{\sqrt{n} } } ]

                                          = [ 24.9-2.896 \times {\frac{2.6}{\sqrt{9} } } , 24.9+2.896 \times {\frac{2.6}{\sqrt{9} } } ]

                                          = [22.4 mg , 27.4 mg]

Therefore, 98% confidence interval for the mean nicotine content of this brand of cigarette is [22.4 mg , 27.4 mg].

No, we don't agree on the claim of FDA that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette because as we can see in the above confidence interval that the value 28.4 does not fall in the 98% confidence interval.

5 0
2 years ago
Other questions:
  • 6+8x2=5x<br><br> A. –2<br><br> B. –1<br><br> C. 1/3<br><br> D. \(3\)
    14·1 answer
  • A teacher randomly selects one student from a group of students where 12 are wearing a black shirt, 8 are wearing a red shirt, a
    5·2 answers
  • Can you guys help me ?
    9·2 answers
  • Gabe Amodeo, a nuclear physicist needs 60 liters of a 40% acid solution. He currently has a 20% solution and a 50% solution. How
    14·2 answers
  • 10.
    13·1 answer
  • 3×2+6÷2<br><br>easy points so just answer it
    15·2 answers
  • Use integers to represent the values in the statement.
    7·1 answer
  • What is the improper fraction of 17/2
    9·2 answers
  • The sum of the base and height of a triangle is 14 cm. Which of the following equations could be used to find the maximum area o
    15·1 answer
  • Express the area of the entire triangle?<br> What is the area?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!