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joja [24]
3 years ago
10

The partial factorization of x2 – x – 12 is modeled with algebra tiles.Which unit tiles are needed to complete the factorization

?
Mathematics
2 answers:
S_A_V [24]3 years ago
3 0
Please write that as x^2 - x - 12 (the "^" symbol denotes exponentiation).

x^2 - x - 12 factors to (x + 3)(x - 4),  Check this by multiplication:

x^2 + 3x - 4x - 12 = x^2 - x - 12 (OK).
astra-53 [7]3 years ago
3 0

Answer: The unit of tiles that are needed to complete the factorization are

(x-4)(x+3)

Step-by-step explanation:

Since we have given that

x^2-x-12=0

We need to factorise the above quadratic equation:

We use "Split the middle term":

x^2-x-12=0\\\\x^2-4x+3x-12=0\\\\x(x-4)+3(x-4)=0\\\\(x-4)(x+3)=0

Hence, the unit of tiles that are needed to complete the factorization are

(x-4)(x+3)

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Answer:

    x = 14

Step-by-step explanation:

1.1     Pull out like factors :

  2x - 20  =   2 • (x - 10)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    x-10 = 0  

Add  10  to both sides of the equation :  

                     x = 10  

One solution was found :

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3 years ago
My question is: What is 13 times 2, divided by 7, subtracted by 10, finally added by 82!
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Factor the expression completely.
evablogger [386]

Answer:

Factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

Step-by-step explanation:

We need to factor the expression xy^4+x^4y^4 completely

We need to find common terms in the expression.

Looking at the expression, we get xy^4 is common in both terms, so we can write:

xy^4+x^4y^4\\=xy^4(1+x^3)

So, taking out the common expression we get: xy^4(1+x^3)

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we get:

xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)

Therefor factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

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