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kvasek [131]
3 years ago
12

Help me and don't put wrong answer. 30 points.

Mathematics
2 answers:
AveGali [126]3 years ago
8 0

Answer:

House of Scorpion I know this one, It's a Metaphor. And if your looking for the rest of the answers go to quizziz House of scorpion final exam if you want all answers

Step-by-step explanation:

vovangra [49]3 years ago
4 0

Answer:

I believe this is a METAPHOR cause you cant really throw your voice as rope.

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I need help please and thank you
rusak2 [61]

Answer:

400

Step-by-step explanation:

Movies, drinks and candies are independent events and you can choose one for each.

Movie: 10 options can be selected

drinks: 5

candy: 8

All types: 10 x 5 x 8 = 400

7 0
2 years ago
Determine the x-coordinate that would yield a y-coordinate of 30, assuming the pair follows the same trend that
malfutka [58]

Answer:

b

Step-by-step explanation:

4 0
2 years ago
Find the area of the shaded region
Levart [38]

Answer:

Answers below

Step-by-step explanation:

7. Area of shape - area of small shape

A(s) = 5*5 = 25 - A(ss) = 3 = 25-3 = 22

8. Area of shape - area of small shape

A(s) = 4*2 = 8 - A(ss) = 1 = 8-1 = 7

5 0
2 years ago
The question is in the picture
PtichkaEL [24]

Answer:

16

Step-by-step explanation:

18,903

3 0
1 year ago
100 POINTS
Shkiper50 [21]

Answer:

  6√3 ±3 ≈ {7.392, 13.392}

Step-by-step explanation:

The length of AB is the long side of a right triangle with hypotenuse CD and short side (AC -BD). The desired radius values will be half the length of EF, with AE added or subtracted.

__

<h3>length of AB</h3>

Radii AC and BD are perpendicular to the points of tangency at A and B. They differ in length by AC -BD = 12 -9 = 3 units.

A right triangle can be drawn as in the attached figure, where it is shaded and labeled with vertices A, B, C. Its long leg (AB in the attachment) is the long leg of the right triangle with hypotenuse 21 and short leg 3. The length of that leg is found from the Pythagorean theorem to be ...

  AB = √(21² -3²) = √432 = 12√3

<h3>tangent circle radii</h3>

This is the same as the distance EF. Half this length, 6√3, is the distance from the midpoint of EF to E or F. The radii of the tangent circles to circles E and F will be (EF/2 ±3). Those values are ...

  6√3 ±3 ≈ {7.392, 13.392}

5 0
1 year ago
Read 2 more answers
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