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nordsb [41]
3 years ago
12

Show all work. PLEASE HELP!!!!

Mathematics
1 answer:
34kurt3 years ago
7 0
(a) Using the table, give the values fo rthe inverse


1) original table of values:


x      1     2     3    4    5

f(x)   0     1     1    5    3


2) The inverse of the function is obtained by exchanging x and f(x), this is:


                   ( x, f(x) ) → ( f(x), x)


3) So, the table of values of the inverse of the given function is:


x          0    1     1      5     3

f⁻¹ (x)   0     1     2     3     4


(b) Is the inverse a function?


No, the inverse is not a function, since the table of the inverse shows that the x -value 1 has two different images.


This ambigüity is opposite to the definition of a function, which requires that any input value has only one output. For that reason, the inverse is not a function. You cannot tell whether the image of 1 is 1 or 2, because both are images of the same value.
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The constant is 3 because it has no variable. 
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Choose the equation that represents the graph below: (1 point) Graph of a line passing through points 0 comma 6 and 9 comma 0 y
aleksklad [387]

Answer:

Option C is correct.

Equation of a line y=\frac{-2}{3}x+6 passing through (0,6) and (9,0).

Explanation:

Given the two points (0, 6) and (9 ,0).

To find the equation for the given two points (x_{1},y_{1}) and (x_{2},y_{2}) is,

y-y_{1}=m(x-x_{1}); where m is the slope and is given by:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

First find the slope m:

m=\frac{0-6}{9-0} =\frac{-6}{9} =\frac{-2}{3}

Substitute this value in equation of line:

y-6=\frac{-2}{3} (x-0) or

y-6=\frac{-2}{3} x

⇒ y=\frac{-2}{3}x+6

Therefore, the equation for the given point is:  y=\frac{-2}{3}x+6


7 0
3 years ago
Solve the equation 4(3y-1)-3(2y)=6​
olga nikolaevna [1]

Answer:

4(3y - 1) - 3(2y) = 6

Remove backets

12y - 4 - 6y = 6

Group and Evaluate like terms

12y - 6y = 6 + 4

6y = 10

y = 10 \div 6

y = 1.67

y =  \frac{5}{3}

6 0
3 years ago
Confused. if you are sure please verify​
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Answer:

the stamen is correct not sure abt the flowers one i don't think it's right

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