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Soloha48 [4]
3 years ago
11

In a bag, there are cards each with one of the numbers {1, 2, 3, 4, 5} written on them. Kenneth reaches into the bag, selects a

card, and then replaces it. He repeats this 16 times with the following results.
Number on selected card 1 2 3 4 5

Frequency 5 3 2 4 2


What is the relative frequency that Kenneth selects the card with 4 written on it? Enter your answer in the box.


[]%
Mathematics
2 answers:
Leviafan [203]3 years ago
6 0
The relative frequency of drawing a 4 is 25%.

A relative frequency gives us the fraction of times an event occurs.

Kenneth drew the 4 card 4 times out of 16 draws; this gives us 4/16 = 1/4 = 25%.
Nat2105 [25]3 years ago
5 0
4/16 or 25% have a good day
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Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E
Lina20 [59]

Answer:

A, B, F

Step-by-step explanation:

2/3 - x + 1/6 = 6x

Collect like terms

2/3 + 1/6 = 6x + x

(4+1) / 6 = 7x

5/6 = 7x

x = 5/6 ÷ 7

= 5/6 × 1/7

x = 5/42

a) 4 - 6x + 1 = 36x

4 + 1 = 36x + 6x

5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

b) 5/6 - x = 6x

5/6 = 6x + x

5/6 = 7x

This is equivalent to the third step of the simplification

c) 4 - x + 1 = 6x

4 + 1 = 6x + x

5 = 7x

x = 5/7

Not equivalent to any of the steps in the simplification above

d) 5/6 + x = 6x

5/6 = 6x - x

5/6 = 5x

x = 5/6 ÷ 5

= 5/6 × 1/5

x = 5/30

Not equivalent to any of the steps in the simplification above

e) 5 = 30x

x = 5/30

Not equivalent to any of the steps in the simplification above

f) 5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

4 0
3 years ago
Find x<br><br> 5x-7+8x-55<br><br> 13 POINTS <br><br> Show work please
Law Incorporation [45]

Combine like terms. The 5x is grouped to the 8x and the -7 isgrouped with the -55.

This means 5x + 8x = 13x and -7 - 55 = -62

The new expression is 13x - 62. We can't find the exact value of x because the expression wasn't set equal to anything.

3 0
4 years ago
Read 2 more answers
A polygon has its vertices at the following points.
seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

BC = |7-4| = 3

CD = \sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0
3 years ago
Divide <br> (6-q+8q^3-4q^2)/(2q-2)
mestny [16]

Answer:


Step-by-step explanation:

        4q2 + 2q + 3                

 (2q - 2)  l  _  8q3  -  4q2  -  q  +  6                                        

                    8q3  -  8q2                      

                           _  4q2  -  q    

                               4q2 - 4q    

                                     _  3q  +  6  

                                        6q   +  6        

                                       -3q (remainder)  


  4q2 + 2q + 3 -3q / (2q - 2)      


hope this helps

4 0
3 years ago
HELP PLEASE ASAP
olga2289 [7]

Answer: a) degree and sign

b) end behavior: left side → +∞, right side → -∞

c) x-intercepts: x = -1.3, 0.3, 1.0

<u>Step-by-step explanation:</u>

end behavior can be determined by two things:

1) the degree of the polynomial:

  • if the degree is an even number, then the end behavior will be the same for both the left and right sides.
  • if the degree is an odd number, then the end behavior will be different for both the left and right sides.

2) the sign of the leading coefficient:

  • If the leading coefficient is positive, then the end behavior of the right side goes to positive infinity
  • If the leading coefficient is negative, then the end behavior of the right side goes to negative infinity

W(x) = -5x³ + 7x - 2

Degree: 3 (odd)

Leading Coefficient: negative

So, end behavior is: right side goes to negative infinity, right side goes to positive infinity.


See attachment for x-intercepts. <em>I set the x-axis to represent tenths </em>

5 0
3 years ago
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