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andre [41]
3 years ago
8

Convert 19(pi)/4 to degrees

Mathematics
1 answer:
Anni [7]3 years ago
5 0
Formula to convert degrees in radians 7 vice versa

(Degree)/180° = Radian/π

Degree/180° = (19π/4)/π. Note that (19π/4)/π = (19π/4)÷π =(19π/4)x(1/<span>π)
= 19/4 = 4.75</span>

Degree/180°= 4.75/π

Cross multiplication: Degree x π = 4.75x180° and Degree = (4.75x180)/π
= 272°15 (π = 3.1459)

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Multiply and simplify. 2x4yx⋅6xy2z3
OLEGan [10]

Answer:

The given expression 2x^4yx \times 6xy^2z^3   on multiplying  is 12x^6y^3z^3

Step-by-step explanation:

Consider the given two expressions 2x^4yx and 6xy^2z^3

We have multiply both expressions,

2x^4yx \times 6xy^2z^3

To multiply two terms first multiply constant numbers that is 6 × 2 = 12

For x , y and z apply property of exponent,

x^a\cdot x^b=x^{a+b}

Then power of x together will be,

x^4\cdot x\cdot x=x^{4+1+1}=x^6

Similarly for y powers,

y \cdot y^2=y^{1+2}=y^3

Since first term do not have any expression for z so it will remain same.

Thus, the given expression  on multiplying become,

2x^4yx \times 6xy^2z^3 is 12x^6y^3z^3




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3 years ago
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grandymaker [24]

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Step-by-step explanation:

5 0
3 years ago
A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and
goldenfox [79]

Answer:

Option D

Step-by-step explanation:

A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.

Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?

We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.

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The x-coordinate of the vertex of the equation y = 2x2 − 4x + 12 The x-coordinate of the vertex of the equation y = 4x2 + 8x + 3
dolphi86 [110]

So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is x=\frac{-b}{2a}, with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:

y = 2x^2 − 4x + 12: x=\frac{4}{2*2}=\frac{4}{4}=1

y = 4x^2 + 8x + 3: x=\frac{-8}{2*4}=\frac{-8}{8}=-1

In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.

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