Question

in a sample of 10 cards, 4 are red and 6 are blue. if 2 cards are selected at random from the sample, one at a time without replacement, what is the probability that both cards are not blue?

Answer 1

It May Be..... Likely

Answer 2

If we want to find the probability that both cards are NOT blue, then we are basically finding the probability that both cards are red:

4/10 * 3/9 = 2/15

We did 3/9 because we already took away one red, which we did not replace.

So, the answer is 2/15.