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WINSTONCH [101]
4 years ago
8

Find the length of GH!

Mathematics
2 answers:
Sati [7]4 years ago
7 0

Answer:

A

Step-by-step explanation:

Calculate the length using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = G(6, 5) and (x₂, y₂ ) = H(8, 9)

GH = \sqrt{(8-6)^2+(9-5)^2}

      = \sqrt{2^2+4^2}

      = \sqrt{4+16}

      = \sqrt{20} ≈ 4.5 → A

kotegsom [21]4 years ago
4 0
Distance formula is square root of (x2-x1)^2 plus (y2-y1)^2
Which is the square root (6-8)^2 plus (5-9)^2
Which is 4.47
Which is approximately 4.5 hope this helps ;)
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bixtya [17]
The two equations in y-intercept form are:
y=-x+2 and y=-x+10

You have to graph them to find the solution, which is the point they intercept each other.

Both lines have the same slope so they will never intercept which means they have no solution.

So, the answer is no solution.

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7 0
3 years ago
Consider the ODE, dy dx = y 2 1 + x (2) subject to condition y = 1 when x = 0, use your Euler code from class (modified if neces
makkiz [27]

Answer:

Computation.

Step-by-step explanation:

I'm not really sure if that's the analytical solution of the inital value problem,

because y(0)=11-ln(1-0)(3)=11. Howevwer, let us procede with the given values...

Let us assume that we are going to use euler with n=2 (two steps) and h=0.2(the size of each step)

The update rules of the Euler Methode are

X_i = X_{i-1}+h=X_0+ih

m_i=\dfrac{dY}{dX} \biggr \rvert_{x_i} \\\\Y_{i+1}=m_i\cdot h+y_i

Since the initial value problem tells us that Y=1 when X=0, we know that

X_0=0 and that Y_0=1. Then, we have

X_0=0\\\\X_1=0.2\\\\X_2=0.4

and

Y_0=1\\\\m_0=21 \cdot Y_0 + X_0 \cdot 2=21 \cdot 1 + 0=21\\\\Y_1=0.2 \cdot 21 + 1 =5.2\\\\m_1=21 \cdot Y_1 + X_1\cdot 2=21 \cdot 5.2 + 0.2 \cdot 2=109.6\\ \\Y_2=m_1 \cdot h + Y_1 = 109.6 \cdot 0.2 + 5.2= 27.12

which gives us the points (0,1), (0.2, 5.2) and (0.4, 27.12).

Now, since we want to compare the analyticaland the Euler result, we first compute the value of y=11-ln(1-x)(3) for the values x=0, 0.2 and 0.4. We get that

y(0)=11-\ln(1-0)(3)=11-ln(1)(3)=11\\\\Y(1)=11-\ln(1-0.2)(3)=11.67\\\\Y(2)=11-\ln(1-0.4)(3)=12.53

and we compute Y(i)-Y_i for each i.

It holds

Y(0)-Y_0=11-1=10\\\\Y(1)-Y_1=11.67-5.2=6.47\\\\Y(2)-Y_2=12.53-27.12=-14.59

which tells us that we have a really bad approximation, as I already stated there must be a mistake in the analytical solution since the intial values don't coincide. Also note that the curve that we get using the euler methose is growing faster than the analitical solution.

4 0
3 years ago
the number of people with one type of flu doubles every day for several days what type of function represents this pattern
svet-max [94.6K]

Answer:

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8 0
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Hope I helped!!
 
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4 years ago
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elixir [45]
The figure is a parallelogram.
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