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inna [77]
3 years ago
9

1. You mix the letters S, U, M, M, E, and R in a bag. Without looking, you select one letter. Find the probability of each event

as a fraction and as a percent.
Mathematics
2 answers:
Lena [83]3 years ago
8 0
Sample space ={S, U, M, M, E, R} = 6 outcomes.  Event selecting S: P(S) =1/6 = 16.67% Event selecting U: P(U) =1/6 = 16.67% Event selecting M: P(M) =2/6 = 1/3 = 33.34% Event selecting E: P(E) =1/6 = 16.67% Event selecting R: P(R) =1/6 = 16.67%
lys-0071 [83]3 years ago
5 0
Sample space ={S, U, M, M, E, R} = 6 outcomes.  Event selecting S: P(S) =1/6 = 16.67% Event selecting U: P(U) =1/6 = 16.67% Event selecting M: P(M) =2/6 = 1/3 = 33.34% Event selecting E: P(E) =1/6 = 16.67% Event selecting R: P(R) =1/6 = 16.67%
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Answer:

38.13 m^2

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the area of a rectangle =b*h

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area of a semi circle=(pi*r^2)/2

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The drama club needs to sell 50 tickets to the school play. So far, they have sold 9 tickets . What percent of their target have
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Read 2 more answers
The Table Shows a proportional relationship between x and y for each Value of x and y match it to the correct unit rate y/x in i
Elden [556K]

The correct proportions are given as follows:

  • x = 3, y = 27: 9/1.
  • x = 9, y = 81: 9/1.
  • x = 21, y = 126: 6/1.
  • x = 14, y = 84: 6/1.
  • x = 12, y = 36: 3/1.
  • x = 15, y = 45: 3/1.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The proportions for this problem are given dividing y by x, hence:

  • x = 3, y = 27: 27/3 = 9, hence 9/1 has to be marked.
  • x = 9, y = 81: 81/9 = 9, hence 9/1 has to be marked.
  • x = 21, y = 126: 126/6 = 6, hence 6/1 has to be marked.
  • x = 14, y = 84: 84/14 = 6, hence 6/1 has to be marked.
  • x = 12, y = 36: 36/12 = 3, hence 3/1 has to be marked.
  • x = 15, y = 45: 45/15 = 3, hence 3/1 has to be marked.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

8 0
2 years ago
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