1. You mix the letters S, U, M, M, E, and R in a bag. Without looking, you select one letter. Find the probability of each event as a fraction and as a percent.
2 answers:
Sample space ={S, U, M, M, E, R} = 6 outcomes. Event selecting S: P(S) =1/6 = 16.67% Event selecting U: P(U) =1/6 = 16.67% Event selecting M: P(M) =2/6 = 1/3 = 33.34% Event selecting E: P(E) =1/6 = 16.67% Event selecting R: P(R) =1/6 = 16.67%
Sample space ={S, U, M, M, E, R} = 6 outcomes. Event selecting S: P(S) =1/6 = 16.67% Event selecting U: P(U) =1/6 = 16.67% Event selecting M: P(M) =2/6 = 1/3 = 33.34% Event selecting E: P(E) =1/6 = 16.67% Event selecting R: P(R) =1/6 = 16.67%
You might be interested in
Answer:
emngtehrge
Step-by-step explanation:
egrbrrg
Answer:
Option C, Y and Z appear to be parallel lines
Hope this helps!
#9: 1 and 1 seventh #10: 1.23 #11: 0.35
In accordance with Pythagoras theorem , 7^2 + 13^2 = x^2 49 + 169 = x^2 218 = x^2 √(218) = x 14.764 = x . Could u please manage with the triplet .. . Sorry abt that
Answer:
chicken tender
Step-by-step explanation:
rgerr