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Gnom [1K]
3 years ago
9

Can someone help me please

Mathematics
2 answers:
Marysya12 [62]3 years ago
7 0

Answer:

4π, 12.5, 4+2π, 6

Step-by-step explanation:

4π=12.56637

12.5=12.5

4+2π= 10.2831853

6=6

Fofino [41]3 years ago
6 0

Answer: Least to greatest: 6, 4+2n, 12.5, 4n

Step-by-step explanation:

pi = 3.14

4n = 12.56

4 + 2n = 10.28

Least to greatest: 6, 4+2n, 12.5, 4n

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Read 2 more answers
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

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Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

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∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

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