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vagabundo [1.1K]
3 years ago
8

In the diagram a || b, if m∠6 = 21°, what is m∠4?

Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:D

Step-by-step explanation:

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Find the missing exponent.
777dan777 [17]

Answer: what missing exponent?

Step-by-step explanation:

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3 years ago
Evaluate the expression 2l+2w for I=5.7 and w=6.2
inessss [21]

Answer:

23.8

Step-by-step explanation:

2(5.7) + 2(6.2)

11.4 + 12.4

23.8

5 0
3 years ago
A) Write ²
I am Lyosha [343]

Answer:

see explanation

Step-by-step explanation:

(a)

x² - 2x - 4

using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² - 2x

= x² + 2(- 1)x + 1 - 1 - 4

= (x - 1)² - 5

with c = - 1 and d = - 5

(b)

x² - 2x - 4 = 0 ← using result from (a) , that is

(x - 1)² - 5 = 0 ( add 5 to both sides )

(x - 1)² = 5 ( take the square root of both sides )

x - 1 = ± \sqrt{5} ( add 1 to both sides )

x = 1 ± \sqrt{5}

5 0
2 years ago
How are the expressions equivalent? ​
Alina [70]

Answer:

Step-by-step explanation:

They R equivalent because 1 half and two half’s equal A

3 0
3 years ago
Read 2 more answers
Triangle in space with vertices P= (1, 0, 0), Q = (0,1,0), R=(0, 0, 2), find angle at P P=​
vagabundo [1.1K]

Answer:

  71.6°

Step-by-step explanation:

The angle can be found from the dot product of PQ and PR.

  PQ·PR = |PQ|×|PR|×cos(α)

where α is the angle between the two segments.

  cos(α) = (Q -P)·(R -P)/(|Q -P|×|R -P|)

  = ((0, 1, 0) -(1, 0, 0))·((0, 0, 2) -(1, 0, 0))/(|Q -P|×|R -P|)

  = (-1, 1, 0)·(-1, 0, 2)/(√(((-1)² +1²)((-1²) +2²)) = (1+0+0)/√10

  α = arccos(1/√10) ≈ 71.6°

The angle at P is about 71.6°.

_____

<em>Additional comment</em>

The side lengths of the triangle are √2, √5, √5. As we have seen, the angle at P is bounded by the sides of length √2 and √5. The law of cosines can also be used to arrive at the angle between these sides.

4 0
2 years ago
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