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yuradex [85]
3 years ago
8

A hot chocolate recipe calls for three teaspoons of cocoa for every cup of milk. How many teaspoons of cocoa are needed for a ba

tch that uses six cups of milk?
Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

18 tsp of cocoa

Step-by-step explanation:

3 tsp : 1 cup

? tsp : 6 cups

6 / 1 = 6

3 x 6 = 18

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It rains 7 out of every 10 days.<br><br> What is the chance of rain on one day?
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if it rains 7 out of 10 days the chance of rain for one day is 70%

Step-by-step explanation:

8 0
3 years ago
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Anastaziya [24]

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The answer is G

If you do the line trick you only get 1 interception on the line each time.

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3 years ago
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Solve the following problem.
Hoochie [10]
47 1/2 divided by 50 1/3

= 95/2 ………….  151/3

= 95/2  times by   3/151

= 285/302 of an hour. 

0.9437 as a decimal. 

Which is 56.6 minutes. 
5 0
4 years ago
A gardener can increase the number of dahlia plants in an annual garden by either buying new bulbs each year or dividing the exi
erik [133]

Answer:

Step-by-step explanation:

Part A

If the gardener increases the number of dahlia plants by buying the new bulbs,

Let the equation representing year (x) and number of bulbs purchased (y) is,

y = mx + b

Here, m = Number of plants purchased each year

b = Initial numbers of plants

For x = 0, and y = 6,

6 = m(0) + b

b = 6

For x = 1, y = 56,

56 = m(1) + 6

m = 50

Therefore, equation for this method of increasing the numbers of plants will be,

y = 50x+ 6

Let the equation for the second method of increasing the number of plants is represented by the equation,

y = a(b)ˣ

From the data given in the table,

For x = 0, y = 6

6 = a(b)⁰

a = 6

For x = 1, y = 12

12 = 6(b)¹

b = 2

Therefore, equation representing the second method (By diving the existing bulbs) will be,

y = 6(2)ˣ

Part B

By substituting the value of x = 10 years,

Method - 1

y = 50(10) + 6

y = 506 plants

Method - 2

y  = 6(2)¹⁰

y = 6144 plants

Part C

After 5 years number of plants by method - 1,

y = 50(5) + 6

  = 256

After 5 years number of plants by method - 2,

y = 6(2)⁵

y = 192

Similarly, After 10 years number of plants by method - 1,

y = 50(10) + 6

  = 506

By method - 2,

y = 6(2)¹⁰

y = 6144

Since, number of plants after 5 years are less by the second method as compared to method 1

But after 10 years second method results the number of plants more than method-1,

Therefore, gardener should adopt method 2 for increasing the numbers of plants.  

6 0
3 years ago
What is the least common multiple of 46, 49, and 17?
Lesechka [4]

Answer:

38318

Step-by-step explanation:

Break the numbers into prime factors

46 = 23*2

49 = 7*7

17 = 17*1

The least common multiple is

23*2*7*7*17 = 38318

6 0
3 years ago
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