I need help with this one question 8r - 5q = 3 solve for q how do i go about this

Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the

adelina 88 [10]

Answer:

$200 + 0.07m \leq 230$

A maximum of $\approx$ 428 miles is the distance what Divya can travel.

Step-by-step explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive = $m$ miles

Charges for one mile = $0.07

Charges for $m$ miles = $0.07 $m$

Total charges for renting and $m$ miles = Rental charges + Operational charges

Total charges for renting and $m$ miles = $200 + $0.07 $m$

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:

$200 + 0.07m \leq 230$

Subtracting 200 from both the sides:

$0.07m \leq 30$

Dividing both sides with 0.07:

$m \leq \dfrac{30}{0.07}\\m\leq 428.6$

Therefore, a maximum of $\approx$ 428 miles is the distance what Divya can travel.

8 0

3 years ago

Does anyone know how to do this HELP

Andrew [12]

Answer:

$3n-6.4$

Step-by-step explanation:

$-1.5(4-n)+2.8-1.5(4-n)+2.8$

Collect like terms:

$(-1.5(4-n)-1.5(4-n))+(2.8+2.8)$

Simplify:

$-3(4-n)+5.6$

Expand:

$-12+3n+5.6$

Collect like terms:

$3n+(-12+5.6)$

Simplify:

$3n-6.4$

4 0

3 years ago

Read 2 more answers

Please help me on my math homework?

stiks02 [169]

Number 1 is -4/3/8 here u go

4 0

3 years ago

The first difference of a sequence is the arithmetic sequence

ad-work [718]

Answer:

a). 1, 3, 5, 7, 9, 11

b). 4, 6, 8, 10, 12, 14

c). 28, 30, 32, 34, 36, 38

Step-by-step explanation:

Solution for question (a):

The first difference of a sequence is the arithmetic sequence;

2, 4, 6, 8, 10

As clearly shown, the common difference (d) is 2.

This sequence, above, is an arithmetic sequence.

If the first term of an arithmetic sequence (AP) is 1, then the first six terms would be:

1, 3, 5, 7, 9, 11

Solution for question (b):

If the sum of the first two terms of an AP is ten,

Lets say the first term is x and the second term is x + 2 then;

x + (x + 2) = 10

2x = 10 - 2

x = 4

So the first term is 4 and the six terms of the AP are:

4, 6, 8, 10, 12, 14

Solution for question (c):

If the fifth term of an AP is 36 then,

To find the nth term in an AP we use the formula;

$T_{n} = a + (n - 1)d$ (where $T_{n}$ is the nth term, $a$ is the first term and $d$ is the common difference).

36 = a + (5 - 1)2

36 = a + 8

a = 36 - 8 = 28

So the first term is 28 and the first terms are;

28, 30, 32, 34, 36, 38

3 0

3 years ago

You put $2000 in an account with a simple interest rate of 1.5%. How long does it take for the account to earn $60?

djverab [1.8K]

Answer:

2 years

Step-by-step explanation:

Simple interest is calculated using the formula: I = prt, where I = the amount of interest earned, p = principal amount, r = rate and t = time. In this case, you know the principal = $2000, the rate = 1.5% or 0.015 and the I = $60, so you are solving for time 't':

I = prt or $60 = $2000(0.015)t

Simplify: 60 = 30t

Divide both sides by 30: 60/30 = 30t/30 or t = 2 years.

3 0

3 years ago