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oksian1 [2.3K]
3 years ago
6

Kenji earned the test scores below in English class. 79,91,93,85,86 and 88. After his next test, his mean and median scores both

change to 88. How much does he earn on this test?
Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

fishsticks

Step-by-step explanation:

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Follow the steps below to find the mean for the set of data. Use the work shown to help you. Data set: 6, 5, 8, 5, 9, 6, 7, 5, 1
lbvjy [14]

Answer:

7

Step-by-step explanation: 6 + 5 + 8 + 5 + 9 + 6 + 7 + 5 + 12 = 63 so now u just divide that by 9  

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3 years ago
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The hospital buys cereal bars in packs of 4. In one day they sell 58 cereal bars. How many packs of cereal bars did they use tha
forsale [732]
Since the cereal bars are bought in a pack of 4 you would divide 58 by 4 to get the amount they used that day . 
58/4 = 14 and a half packs
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3 years ago
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Emma, Brandy, and Damian will cut a rope that is 29.8 feet long into 3 jump ropes. Each of the three jump ropes will be the same
Vesnalui [34]

Answer:

The length of each rope is 9.93 feet (Approx).

Step-by-step explanation:

As given

Emma, Brandy, and Damian will cut a rope that is 29.8 feet long into 3 jump ropes.

Each of the three jump ropes will be the same length.

Thus

Length\ of\ each\ rope = \frac{29.8}{3}

Length\ of\ each\ rope = 9.93\ feet(Approx)

Therefore the length of the each rope is 9.93 feet (Approx).



3 0
3 years ago
The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal
Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The other parameters are given as follows:

\overline{x} = 111000, \sigma = 36730, n = 36

Hence, the lower bound of the interval is:

\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
Pls help me <br><br> i don't understand it
Savatey [412]

Replace x and y with the given values and solve the equations:

A) 3(5) + 2 = 17

B) 2(5)^2 = 50

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