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USPshnik [31]
3 years ago
7

Please help me with this

Mathematics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

Hey there!

The answer is 6/7h=4.

This means that 6/7 of his brother's height is four feet, which is Bryce's height.

Let me know if this helps :)

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15x^2+21x+6 that’s the answer
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Write the whole number 7420 in expanded form
bija089 [108]

Expanded Notation Form:

 7,000  

+ 400  

+ 20  

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Expanded Factors Form:

 7 × 1,000  

+ 4 × 100  

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Expanded Exponential Form:

7 × 103

+ 4 × 102

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Word Form:

seven thousand four hundred twenty

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What is the slope of a line that is parralel to y =3x+5
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3

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Amid needs 32.9 meters of fabric to make one tent. he has an order for 12 tents. how many meters of fabric does he need? a. 367.
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6 0
3 years ago
Suppose 120 geology students measure the mass of an ore sample. Due to human error and limitations in the reliability of the​ ba
Nonamiya [84]

Answer:

For this case we want this probability:

P( 75

And we can use the z score formula given by:

z = \frac{87-81}{3} = 2

z = \frac{75-81}{3} = -2

So we want the probability for the values within two deviations from the mean and from the empirical rule we know that we have approximately 0.95 or 95% of the values within two deviations from the true mean.

And since we have a total of 120 students we expect:

120*0.95 = 114 between 75g and 87 g

Step-by-step explanation:

Previous concepts

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the courtship time (minutes).

From the problem we have the mean and the standard deviation for the random variable X. E(X)=81, Sd(X)=3

So we can assume \mu=81 , \sigma=3

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Solution to the problem

For this case we want this probability:

P( 75

And we can use the z score formula given by:

z = \frac{87-81}{3} = 2

z = \frac{75-81}{3} = -2

So we want the probability for the values within two deviations from the mean and from the empirical rule we know that we have approximately 0.95 or 95% of the values within two deviations from the true mean.

And since we have a total of 120 students we expect:

120*0.95 = 114 between 75g and 87 g

5 0
3 years ago
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