Question

What is the negative solution to this equation? 4x^2+12x=135​

Answer 1

Answer:

$-\frac{15}{2}$

Step-by-step explanation:

$\mathrm{Subtract\:}135\mathrm{\:from\:both\:sides}$

$4x^2+12x-135=135-135$

$\mathrm{Simplify}$

$4x^2+12x-135=0$

$x1, 2=−b±√b2−4ac2a For a=4, b=12, c=−135x1, 2=−12±√122−4· 4(−135)2· 4$