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4 years ago

What is the second smallest number that has 1,2,3,4,5 as factors

Mathematics

1 answer:

skelet666 [1.2K]4 years ago

4 0

120 because of course 1 can go into anything, 2 would be 60, 3 would be 40, 4 would be 30 and 5 would be 24

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Pls hurry I’m running out of time<br><br> Will mark brainliest

murzikaleks [220]

13x - 7

You get this answer by adding the two together because mWEV is equivalent to the two known angles put together.

Hope this helps!

3 0

3 years ago

A proportion is shown. x36=1512 What is the value of x?

Fudgin [204]

42 is the right answer

3 0

3 years ago

Read 2 more answers

At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100

alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

$M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}$

For a 95% CI, the value of z=1.96.

$1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05$

8 0

3 years ago

Choose Yes Or No To Tell if the fraction 4/9 will make each equation True.

BlackZzzverrR [31]

Answer:

true, true, false, true

Step-by-step explanation:

(4/9)*63=28

(4/9)*18=8

(4/9)*96=42.666667

(4/9)*36=16

5 0

3 years ago

The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr

IgorC [24]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the population mean.

As per given , we have

$H_0:\mu \leq4\\\\ H_a: \mu >4$

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given $\sigma=1$ , so we perform one-tailed z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where $\mu$ = Population mean

$\sigma$ = Population standard deviation

n= sample size

$\overline{x}$ = Sample mean

For n= 18 , $\overline{x}=4.50$ , $\sigma=1$ , $\mu =4$ , we have

$z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12$

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

3 0

3 years ago