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kkurt [141]
2 years ago
15

Solve the following quadratic equation: y=5x2+10x Solutions: x= and x=

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
6 0

Answer:

0 and -2

Step-by-step explanation:

5x^2+10x=0\\5x(x+2)=0\\\\Then\\5x=0\\\\x=\frac{0}{5}==>x_{1}=0 \\x+2=0==> x_{2}=-2

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What is the ratio 175 to 250 written in fraction in LOWEST TERMS?
Lana71 [14]
For 175 : 250 divide them both by 25 to get \frac{7}{10} < \frac{175}{250}
25 goes into 175 > 7 times > 25 into 250 is 10 times! > \frac{7}{10}
For the second one 16 : 40 just divide the top and bottom by 8 since 8 is a common factor of both which will give us \frac{2}{5}.
8 goes into 16, 2 times and 40, 5 times.
5 0
3 years ago
Read 2 more answers
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Please help with any question !! need help
Gre4nikov [31]

Answer:

1/ 4/5

2/ 6/8 = 3/4

3/ 4/5

4/ 4/10 = 2/5

5/ 2/4 = 1/2

4 0
3 years ago
The distance from point A to point B is
Sedaia [141]
The answer will be B-A
2-(-5)
(- -)=+
2+5=7
The answer will be 7
3 0
3 years ago
Read 2 more answers
The graph shows the distance Julian drives on a trip. What is Julian's speed?
lilavasa [31]

Answer:

B. 80 km/h

Step-by-step explanation:

The graph is linear and goes through the origin, so distance is proportional to time, and the constant of proportionality is speed. The desired answer can be read from the point on the graph at time = 1 hour: 80 km.

Julian's speed is 80 kilometers per hour.

6 0
2 years ago
Read 2 more answers
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