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kkurt [141]
2 years ago
15

Solve the following quadratic equation: y=5x2+10x Solutions: x= and x=

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
6 0

Answer:

0 and -2

Step-by-step explanation:

5x^2+10x=0\\5x(x+2)=0\\\\Then\\5x=0\\\\x=\frac{0}{5}==>x_{1}=0 \\x+2=0==> x_{2}=-2

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The marginal price per pound (in dollars) at which a coffee store is willing to supply x pounds of Jamaican Blue Mountain coffee
il63 [147K]

Answer:

Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.

Step-by-step explanation:

We are given the following information in the question:

The marginal price per pound (in dollars) is given by:

p'(x) = \displaystyle\frac{208}{(x+7)^2}

where x is the supply in pounds.

P(x) = \displaystyle\int p'(x)~dx =\displaystyle\int\displaystyle\frac{208}{(x+7)^2}~dx\\\\P(x) = \frac{-208}{(x+7)} + c\\\\\text{where c is the constant of integration.}

The coffee shop is willing to supply 9 pounds per week at a price of $7 per pound.

Thus, we are given that

P(9) = 7

Putting the values, we get,

P(x) = \displaystyle\frac{-208}{(x+7)} + c\\\\P(9) = 7\\\\\displaystyle\frac{-208}{(9+7)} + c = 7\\\\c = 7 + \frac{208}{16} = 20

P(x) = \displaystyle\frac{-208}{(x+7)} + 20

Now, we have to find how many pounds it would be willing to supply at a price of $4 per pound.

P(x) = 4

P(x) = \displaystyle\frac{-208}{(x+7)} + 20 = 4\\\\\frac{-208}{x+7} = -16\\\\x + 7 = 13\\x = 6

Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.

3 0
3 years ago
How Many Squares does the Below given picture. <br> Thanks.
zalisa [80]

Answer:

10

Step-by-step explanation:

6 0
2 years ago
Let’s work with some actual data this time. Go online to research and find a set of real-world data in two variables. The data c
slega [8]

The quadratic regression equation that best fits the data set is y = 32.86x² - 379.14x  + 1369.14

<h3>The data points </h3>

The following table of values represents the data points that would be used to solve this question:

x 3 4 5 6 7 8 9

y 470 416 403 226 314 338 693

Where:

  • x represents years since 2000
  • y represents the annual revenue of a manufacturing company in thousand dollars

<h3>The function of the dataset</h3>

The table of values illustrates a quadratic function.

The function would be calculated using a graphing calculator

From the graphing calculator, we have:

a = 32.86; b = -379.14 and c = 1369.14

A quadratic regression equation is represented as:

y = ax² + bx + c

So, we have:

y = 32.86x² - 379.14x  + 1369.14

Hence, the quadratic regression equation that best fits the data set is y = 32.86x² - 379.14x  + 1369.14

<h3>Why the function type was chosen?</h3>

From the table of values in (a), we can see that as x increases; the value of y decreases and then increases after it reaches a minimum.

This illustrates the behavior of a quadratic regression function

See attachment for the scatter plot

Read more about quadratic regression equation at:

brainly.com/question/14786188

#SPJ1

5 0
2 years ago
Solve for x and y<br> y = 2x + 1<br> y = 4x - 1
Furkat [3]

the answer for y is 3

the answer for x is 1

5 0
2 years ago
What would be the image of Point B(3, 2) after the following transformations have been applied:
Ulleksa [173]

Answer:

(9,6)

Step-by-step explanation:

(6,9)

Because the scale factor is 3 so u r suppose to multiply by 3

6 0
3 years ago
Read 2 more answers
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