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2 years ago

12. WILL MARK BRAINLIEST!! HELP!

Mathematics

2 answers:

IgorC [24]2 years ago

5 0

Step-by-step explanation:

$- \bigg( \frac{2x}{ - xy} \bigg) \\ \\ = - \bigg( \frac{2}{ - y} \bigg) \\ \\ = - \frac{2}{ - y} \\ \\ = \frac{2}{ y}$

lord [1]2 years ago

5 0

$\text{Solve:}\\\\-(\frac{2x}{-xy})\\\\\text{Distribute the negative sign to the numerator:}\\\\(\frac{-2x}{-xy})\\\\\text{Simplify by canceling the like terms and take away the negative sings:}\\\\(\frac{2}{y})\\\\\boxed{\frac{2}{y}}$

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y is directly proportional to x^3. it is known that =5 for a particular value of x. find the value of y when this value of y whe

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Answer:

The value of $y$ when the value of $x$ is multiplied by $\frac{1}{2}$ is $\frac{5}{8}$ .

Step-by-step explanation:

According to the statement, we have the following relationship:

$y = k\cdot x^{3}$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

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If we know that $y_{1} = y$ , $y_{2} = 5$ , $x_{2} = x_{o}$ and $x_{1} = \frac{1}{2}\cdot x_{o}$ , then the value of $y$ when the value of $x$ is multiplied by $\frac{1}{2}$ is:

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The value of $y$ when the value of $x$ is multiplied by $\frac{1}{2}$ is $\frac{5}{8}$ .

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2 years ago

HELP?!? idk what im doing and nobody has asked this. will give brainliest answrr or whatever its called.

Illusion [34]

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Answer:

$\textbf{A. }x=\dfrac{-4\pm2\sqrt{13}}{3}$

Step-by-step explanation:

First of all, subtract 12 from both sides of the equation to put it into standard form:

3x² +8x -12 = 0

Then identify the a, b, c of this form:

ax² +bx +c = 0

You see that a=3, b=8, c=-12.

Now use those values in the quadratic formula for the solutions:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-8\pm\sqrt{8^2-4(3)(-12)}}{2(3)}\\\\x=\dfrac{-8\pm\sqrt{208}}{6}=\dfrac{-8\pm4\sqrt{13}}{6}\\\\\boxed{x=\dfrac{-4\pm2\sqrt{13}}{3}}\qquad\text{factor 2 from numerator and denominator}$

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Step-by-step explanation:

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12. WILL MARK BRAINLIEST!! HELP! ​

12. WILL MARK BRAINLIEST!! HELP!