The first thing you should do is solve the equation yourself.
1) Distribute the 2.
6x + 4 = 2x – 16
2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16
3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12
4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3
To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.
Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>
Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1

∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2

∴ y = 0.12
Answer:
i know the answer but not the equation
Step-by-step explanation:
Option D. 96 is the correct answer.
Explanation:
Let the higher grade be = x
Let the lower grade be = y
As given, The difference of the two grades is 16
or
.... (1)
The sum of one-eighth of the higher grade and one-half of the lower grade is 52.
... (2)
Putting the value of x=16+y in equation (2)






As x=16+y
x=16+80 = 96
Hence, higher grade is 96.
It’s either b or d. Hope this helps! :)