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MrRissso [65]
4 years ago
5

what �is the equation of a line that is perpendicular to the line  y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr

ough the point  ( 6 , 1 )
Mathematics
1 answer:
gladu [14]4 years ago
8 0

Answer:

y=\frac{1}{25}x-\frac{31}{25}

Step-by-step explanation:

y=-25x-5

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

(y-y_0)=m(x-x_0)

y-1=\frac{1}{25} (x-6)

Rearrange for y and collect terms.

y=\frac{1}{25}x-\frac{6}{25}-1\\\\y=\frac{1}{25}x-\frac{31}{25}

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