Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
Step-by-step explanation:
I don't know the answer to this one so could someone please tell me
Thanks
9514 1404 393
Answer:
- late only: 15
- extra-late only: 24
- one type: 43
- total trucks: 105
Step-by-step explanation:
It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.
For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.
Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.
__
a) 15 trucks carried only late
b) 24 trucks carried only extra late
c) 4+15+24 = 43 trucks carried only one type
d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out
We can’t answer this question without more info. It’s clearly a multiple choice question, so you need to provide the answers.