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musickatia [10]
4 years ago
14

Write and solve an equation that means "6 less than a number (x) is 5."

Mathematics
2 answers:
krok68 [10]4 years ago
8 0
X-6=5 is the answer that I got. 6 less than a number(x) means you are subtracting 6 and is 5 means it equals 5. Hope this helps:))
Taya2010 [7]4 years ago
8 0
X-6=5
You should read it how it is written. It is basically saying x minus 6 equals 5.
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Look at the figure. Which construction is illustrated? 7. Which is the equation of the line with slope 3 that contains point (−1
kenny6666 [7]

Answer:

Option B

Step-by-step explanation:

I can't do the 'figure question' because it lacks info, but I can answer the point-slope question.

Point-slope form is: y-y_1=m(x-x_1)

'm' - slope

'(x1, y1)' - point

We are given the slope of 3 and the point (-1, 5).

Replace 'x1', 'y1', and 'm' with the appropriate values.

y-y_1=m(x-x_1)\rightarrow \boxed{y-5=3(x+1)}

Option B should be the correct answer.

7 0
3 years ago
3. Use powers to rewrite these problems:
VLD [36.1K]
A=Y^6
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7 0
3 years ago
The sum of two fractions is 2/3.<br> One fraction is 1/2.<br> What is the other fraction?
Cerrena [4.2K]

Answer:

0.5/3

Step-by-step explanation:

1/2 can be turned into 2/4, which means that to be 1/3, it has to be 1.5/3. 1.5/3 + 0.5/3 equals 2/3.

7 0
2 years ago
Read 2 more answers
Step 3 out of 5:<br> Multiply<br> 7/3 times 3/2= <br><br> 7/3 times 1/2=
Nikitich [7]
The answers are 7/2 and 7/6
6 0
3 years ago
Read 2 more answers
A professor has been teaching accounting for over 20 years. From her experience she knows that 75% of her students do homework r
Nata [24]

Answer:

a) P(B|A) =\frac{P(A and B)}{P(A)}=\frac{0.65}{0.75}=0.867

b) In order to two events can be considered as independent we need to have this condition:

P(A and B) = P(A)*P(B)

If we check the condition we see this:

P(A)*P(B)= 0.75*0.7=0.525 \neq P(A and B)

So since we don't have the condition satisfied the events "do the homework regularly" and "pass the course" are not independent.

Other way to check independence is with the following two conditions:

P(B|A)=P(B) or P(A|B)=P(A), and we see that P(B|A)\neq P(B)  for our case.

Step-by-step explanation:

Data given

Lets define the following events

A: Represent the students who do homework regularly

B: Represent the students who  pass the course

75% of her students do homework regularly

70% of her students pass the course

65% of her students do homework and also pass the course

For this case we have some probabilities given:

P(A) =0.75, P(B) =0.70 and P(A and B)=0.65

Solution to the problem

Part a

On this case we want to find this probability:

P(B|A) the conditional probability (Pass the course given that he does the homework regularly).

By defintion of conditional probability we know that:

P(B|A) =\frac{P(A and B)}{P(A)}

And now we can replace in the conditional formula like this:

P(B|A) =\frac{P(A and B)}{P(A)}=\frac{0.65}{0.75}=0.867

Part b

In order to two events can be considered as independent we need to have this condition:

P(A and B) = P(A)*P(B)

If we check the condition we see this:

P(A)*P(B)= 0.75*0.7=0.525 \neq P(A and B)

So since we don't have the condition satisfied the events "do the homework regularly" and "pass the course" are not independent.

Other way to check independence is with the following two conditions:

P(B|A)=P(B) or P(A|B)=P(A), and we see that P(B|A)\neq P(B)  for our case.

6 0
3 years ago
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