A person is strolling along a moving walkway at a constant velocity of +1.00 m/s with respect to the walkway, which moves at a c
onstant velocity of +0.50 m/s with respect to the ground. an observer on the ground is walking at a constant velocity of -0.2 m/s. what is the velocity of the person on the walkway with respect to the observer on the ground?
1 answer:
Refer to the diagram shown below.
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s
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2 Times
Step-by-step explanation:
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- Light A flashes every 15 seconds.
- Light B flashes every 18 seconds.
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This is done by finding the Least Common Multiple of 15 and 18.
15=3X5
18=
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This means that lights A and B will first flash together after 90 seconds.
Now, 240/90= seconds
Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times
Step-by-step explanation: