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A person is strolling along a moving walkway at a constant velocity of +1.00 m/s with respect to the walkway, which moves at a c
onstant velocity of +0.50 m/s with respect to the ground. an observer on the ground is walking at a constant velocity of -0.2 m/s. what is the velocity of the person on the walkway with respect to the observer on the ground?
1 answer:
Refer to the diagram shown below.
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s
The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s
The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s
Answer: 1.7 m/s
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Answer:
Divide both sides by 9.
Step-by-step explanation:
To find the second step of the equation, we actually have to solve parts of the equation until we get to step 2.
Step 1: Add 23 to both sides.
Step 2: Divide both sides by 9.
Therefore, the second step is divide both sides by 9.
Have a lovely rest of your day/night, and good luck with your assignments! ♡