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3 years ago

1/10 of what number is 17

Mathematics

2 answers:

matrenka [14]3 years ago

7 0

1/10 of 17 is 170. 17 x 10 = 170. Since 17 is one tenth of the number, all we have to do is multiply it by ten.

snow_lady [41]3 years ago

4 0

To solve this we need first find are number that we have to multiply 17 by to get are number. To do this we look at are denominator and because it is 1 over 10 meaning that 17=1 and x=10 all that we have to do is take 17*10=170.

Enjoy!=)

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Help with this measurement question pls

Arisa [49]

Around 10.63 because 400/37.61=10.63

3 0

3 years ago

Read 2 more answers

The Retread Tire Company recaps tires. The fixed annual cost of the recapping operation is $65,000. The variable cost of recappi

trasher [3.6K]

Part a) Total Cost

Total Cost for recapping the tires is the sum of fixed cost and the variable cost. i.e.

The total cost is ( $65,000 fixed) + (15,000 x $7.5)

=$65,000+$112,500

=$177,500

Part b) Total Revenue

Revenue from 1 tire = $25

Total tires recapped = 15000

So, Total revenue = 15000 tires x $25/tire

Total Revenue =$375,000

Part c) Total Profit

Total Profit = Revenue - Cost

Using the above values, we get:

Profit = $375,000 - $177,500

Profit = $197,500

Part d) Break-even Point

Break-even point point occurs where the cost and the revenue of the company are equal. Let the break-even point occurs at x-tires. We can write:

For break-even point

Cost of recapping x tires = Revenue from x tires

65,000 + 7.5 x = 25x

65,000 = 17.5 x

x = 3714 tires

Thus, on recapping 3714 tires, the cost will be equal to the revenue generating 0 profit. This is the break-even point.

3 0

4 years ago

When 142 is added to a number, the result is 64 more than 3 times the number. Find

dmitriy555 [2]

X+142 =3x+64

subtract x from each side

142 = 2x+64

subtract 64 from each side

142-64 = 2x

78=2x

divide by 2

78/2 = x

x=39

The number is 39

8 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$