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AURORKA [14]
3 years ago
9

2 questions please help me :) thanks if you do

Mathematics
2 answers:
yulyashka [42]3 years ago
8 0
My answer for 1 was D and my answer for 2 was A.
mezya [45]3 years ago
5 0

Answer:

(1)   6,4

(2) 5,6

Step-by-step explanation:

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2 years ago
The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
natita [175]

Answer:

68% of jazz CDs play between 45 and 59 minutes.

Step-by-step explanation:

<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?

Let X = <u>playing time of jazz CDs</u>

SO, X ~ Normal(\mu=52, \sigma^{2} =7)

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

Now, according to the 68-95-99.7 rule, it is stated that;

  • 68% of the data values lie within one standard deviation points from the mean.
  • 95% of the data values lie within two standard deviation points from the mean.
  • 99.7% of the data values lie within three standard deviation points from the mean.

Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;

   For 45 minutes, z-score is =  \frac{45-52}{7}  = -1

   For 59 minutes, z-score is =  \frac{59-52}{7}  = 1

This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.

6 0
3 years ago
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