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Aleonysh [2.5K]
3 years ago
12

Thomas solved the equation by completing the square. x2−10x+27=0 show work

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0

Answer:

Values of x will be [5 + √(-2)] and [5 - √(-2)]

Step-by-step explanation:

Thomas soled the equation (x² - 10x + 27) = 0 by completing the square.

x² - 2(5x) + 27 = 0

x² - 2(5x) + 25 - 25 + 27 = 0

(x - 5)² - 25 + 27 = 0

(x - 5)² + 2 = 0

(x - 5)² = - 2

(x - 5) = ±√(-2)

x = 5 ±√(-2)

Therefore, values of x will be [5 + √(-2)] and [5 - √(-2)].

Ber [7]3 years ago
4 0
(x-3)(x-7)=0
x=3,7
hope this helps!
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Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

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∵ Jim goes from 70 meters/minute (beginning speed) to

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∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

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Answer:

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Answer:

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Step-by-step explanation:

Diego was trying to write 2^3 · 2^2

He wrote  2^3·2^2 = 2^3*2 = 2^6  

But this is wrong because when bases are same exponents are added.

This is the law of exponents.

The correct form would be

2^3·2^2 = 2^3+2 = 2^5  

For understanding it better we can write it like this

2^3·2^2 =

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