All categories

4 years ago

Thomas solved the equation by completing the square. x2−10x+27=0 show work

Mathematics

2 answers:

lisabon 2012 [21]4 years ago

5 0

Answer:

Values of x will be [5 + √(-2)] and [5 - √(-2)]

Step-by-step explanation:

Thomas soled the equation (x² - 10x + 27) = 0 by completing the square.

x² - 2(5x) + 27 = 0

x² - 2(5x) + 25 - 25 + 27 = 0

(x - 5)² - 25 + 27 = 0

(x - 5)² + 2 = 0

(x - 5)² = - 2

(x - 5) = ±√(-2)

x = 5 ±√(-2)

Therefore, values of x will be [5 + √(-2)] and [5 - √(-2)].

Ber [7]4 years ago

4 0

(x-3)(x-7)=0
x=3,7
hope this helps!

You might be interested in

Please help me i need this turned in by tonight and i really don’t understand it but i don’t need an explanation i just need the

KATRIN_1 [288]

Answer: 180

Hope it helps

Step by step explanation:

1000*.18=180

5 0

3 years ago

Use prime factorization to reduce each fraction 1. 22/165 2. 35/210

yKpoI14uk [10]

Lets find the prime factorization of 22, 165, 35 and 210. Prime factorization of a number is breaking a number down into the set of prime numbers which multiply together to result in the original number.

The prime factorization of the number 22 is:

$22=2\times11$

Similarly, for 165, 35 and 210 we have

$\begin{gathered} 165=3\times5\times11 \\ 35=5\times7 \\ 210=2\times3\times5\times7 \end{gathered}$

Then, we can solve the given questions.

Question 1.

$\frac{22}{165}=\frac{2\times11}{3\times5\times11}$

so we can cancel out the number 11 and get

$\frac{22}{165}=\frac{2}{3\times5}=\frac{2}{15}$

Then, the answer is

$\frac{2}{15}$

Question 2.

$\frac{35}{210}=\frac{5\times7}{2\times3\times5\times7}$

and we can cancel out the number 5 and 7, then we obtain

$\frac{35}{210}=\frac{1}{2\times3}$

then, the answer is

$\frac{1}{6}$

5 0

1 year ago

Find the distance between the points G(-5, 4) and H(2, 6).

vladimir2022 [97]

Answer:

The answer is

<h2> $\sqrt{53} \: \: or \: \: 7.28 \: \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

G(-5, 4) and H(2, 6)

The distance between them is

$|GH | = \sqrt{ ({ - 5 - 2})^{2} + ({4 - 6})^{2} } \\ = \sqrt{ ({ - 7})^{2} + ( { - 2})^{2} } \: \\ = \sqrt{49 + 4} \\ = \sqrt{53} \: \: \: \: \: \: \: \: \\ = 7.280109$