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irinina [24]
3 years ago
7

Find the distance between the points given. (0,6) and (5,12)

Mathematics
2 answers:
Tresset [83]3 years ago
8 0
We can plug the two points into the distance formula.

\sf~d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(0, 6), (5, 12)
x1 y1 x2  y2

Plug in what we know:

\sf~d=\sqrt{(5-0)^2+(12-6)^2}

Subtract:

\sf~d=\sqrt{(5)^2+(6)^2}

Simplify the exponents:

\sf~d=\sqrt{25+36}

Add:

\sf~d=\sqrt{61}

Simplify the square root:

\sf~d\approx\boxed{\sf7.81}
Elan Coil [88]3 years ago
4 0
d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}} \\d = \sqrt{(5 - 0)^{2} + (12 - 6)^{2}} \\d = \sqrt{(5)^{2} + (6)^{2}} \\d = \sqrt{25 + 36} \\d = \sqrt{61} \\d = 7.8 \\\\(x - h)^{2} + (y - k)^{2} = r^{2} \\(x - 5)^{2} + (y - 6)^{2} = 7.8^{2} \\(x - 5)^{2} + (y - 6)^{2} = 61 \\(h, k) = (5, 6)
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Step-by-step explanation:

Let x = 0.3333333...

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A whAt the theoretical probability
julsineya [31]

Answer:

a.  \frac{1}{6}

b.  \frac{67}{450}

Step-by-step explanation:

Theoretical probability is what we expect to happen and experimental probability is what actually happens.

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There are 6 faces (from 1 to 6) in a number cube. And there is 1 "3". So the probabilty of rolling a 3 is:

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6 0
3 years ago
Which function has a range of<br><br> f(x)≥7
amid [387]

Answer:

While it's true that quadratic functions have no domain restrictions, the range is restricted because x2 ≥ 0. The correct answer is: The domain is all real numbers and the range is all real numbers f(x) such that f(x) ≥ 7.

Step-by-step explanation:

3 0
3 years ago
Write an expression for the model. Find the sum. options: a) 2 + (–3); 1 b) –3 + 2; 5 c) 2 + 3; 5 d) 2 + (–3); –1
Dima020 [189]

Answer:

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

Step-by-step explanation:

When adding integers (positive and negative whole numbers), there are three cases:

  • Positive and positive increases and sum is positive. Ex. 4 + 6 = 10
  • Positive and negative where you subtract and take the sign of the larger number. Ex. 3 + -8 = -5 or -3 + 8 = 5
  • Negative and negative decrease and the sum if negative. Ex. -4 + -6 = -10.

Use these rules to simplify each expression.

a) 2 + (–3) = -1 not 1     FALSE

b) –3 + 2 = -1 not 5      FALSE

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

5 0
3 years ago
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