Answer:
about 280
Step-by-step explanation:
brainliest pls :)
Answer:
5.545
Step-by-step explanation:
This problem can be easily solved by using the law of cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles.
in this case, the formula can be applied in the following way
a^2 = b^2 + c^2 - 2*b*c*cos(α)
Where
a,b,c are each of the sides of the triangle,
α is the angle between sides b and c
(See attached picture)
If we use the formula we get
a^2 = (9)^2 + (6)^2 - 2*(9)(6)*cos(37°)
a^2 = 81 + 36 - 86.2526
a^2 = 30.747
a = sqrt(30.747)
a = 5.545
Answer:
About 609,000 Cowboy stadiums could fit inside of Mount Everest
Step-by-step explanation:
we have
The estimate volume of Mount Everest is at around 
The Dallas Cowboys Stadium has a volume of 
step 1
Convert ft³ to km³
we know that
1 km=3,280.84 ft
so

step 2
To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

Round to the nearest Thousands

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium
There is a high probability of all of them being catfish since there are 8 catfish in total and since 8 were randomly caught. I don’t truly know.
A (1)= -5×3(1)-1
a(1)= -5×3-1
a (1)= -16
A(4)= -5×3(4)-1
a (4)= -5×12-1
a( 4) = -60-1
a(4)= -61
A(8)= -5×3(8)-1
a(8)= -5×24-1
a(8)= -120-1
a(8)= -121
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