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expeople1 [14]
2 years ago
5

Determine whether the pair of actions results in independent or dependent events. Serena picks one marble out of a bag. Then, af

ter replacing the marble, she picks another marble.
A) Dependent; the 1st marble selection will affect the 2nd marble selection.
B) Independent; the 1st marble selection will not affect the 2nd marble selection.
C) Dependent; the 1st marble selection will not affect the 2nd marble selection.
D) Independent; the 1st marble selection will affect the 2nd marble selection.

Please help!
Mathematics
2 answers:
Marianna [84]2 years ago
6 0

Answer:

<h2>B) Independent; the 1st marble selection will not affect the 2nd marble selection.</h2>

Step-by-step explanation:

These events are independent, because Serena replaced the marble which doesn't alter the total number of outcomes to determine the probability of picking another marble.

Therefore, the right asnwer is B.

Remember that independent events are defined as those which don't influence in each other probabilities.

harina [27]2 years ago
4 0

Answer:

B) Independent; the 1st marble selection will not affect the 2nd marble selection.

Step-by-step explanation:

When finding the probability of events in mathematics, we have both independent and dependent events.

Independent events are events that occur when the results of selection of the first events does not affect the results or outcomes of the second events.

Dependent events are the opposite of Independent events. They are events that occur when the results or outcomes obtained from the second events is affected by the results or outcomes from the selection of the first events.

From the question, we can see that the first event is she picked one marble from the bag. The second event is she replaced the marble before picking another marble. By doing this, the total number of possible outcomes for the probabilities of both events remains the same and they are unaffected.

Therefore, we can say that the two events are Independent because the 1st marble selection will not affect the 2nd marble selection.

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Pls help with this ..its to be submitted this monday.....pls pls pls
Svet_ta [14]

Answer:

9pr = 2q^2

Step-by-step explanation:

28.

px^2 + qx + r = 0

If one root is A then the other root is 2A

We have A + 2A = -q/p   and A*2A = r/p

So 3A = -q/p  so A = -q/3p and  A^2  = r/2p  so A = √ (r / 2p)

Equating  these 2 equations:-

-q/3p =  √(r / 2p)

q^2 / 9p^2 = r / 2p

9p^2r = 2pq^2

9pr = 2q^2   (answer)


6 0
3 years ago
Now, you will consider Option 1, setting a maximum shower time of 10 minutes.
matrenka [14]

The maximum shower time is an illustration of mean and median, and the conclusion is to disagree with Blake's claim

<h3>How to interpret the shower time?</h3>

The question is incomplete, as the dataset (and the data elements) are not given.

So, I will answer this question using the following (assumed) dataset:

Shower time (in minutes): 6, 7, 7, 8, 8, 9, 9, 9, 12, 12, 12, 13, 15,

Calculate the mean:

Mean = Sum/Count

So, we have:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 12+ 12+ 12+ 13+ 15)/13

Mean = 9.8

The median is the middle element.

So, we have:

Median = 9

From the question, we have the following assumptions:

  • The shower time of students whose shower times are above 10 minutes, is 10 minutes
  • Other shower time remains unchanged.

So, the dataset becomes: 6, 7, 7, 8, 8, 9, 9, 9, 10, 10, 10, 10, 10

The mean is:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 10+ 10+ 10+ 10+ 10)/13

Mean = 8.7

The median is the middle element.

So, we have:

Median = 9

From the above computation, we have the following table:

               Initial    Final

Mean         9.8        8.7

Median       9         9

Notice that the mean value changed, but it did not go below 8 as claimed by Blake; while the median remains unchanged.

Hence, the conclusion is to disagree with Blake's claim

Read more about mean and median at:

brainly.com/question/14532771

#SPJ1

5 0
2 years ago
HELP ITS AN EMERGENCY HELP HELP FOR 100 POINTS
Alecsey [184]

Answer:

that's easy 4/15- 1/15=3/15,9 15/24-2 9/24=7 6/24, 1 5/1+1 1/1= 2 6/1 there

Step-by-step explanation:

6 0
2 years ago
Let ? = {a, b, c} be a sample space. let m(a) = 1/2, m(b) = 1/3, and m(c) = 1/6. find the probabilities for all eight subsets of
Leviafan [203]
<span>
A= {a,b,c} . Since this set has 3 elements, the number
of its total subset is 2³ = 8 (including the Ф element):

Here below all the subsets of {a,b,c}, with their related probabilities, knowing that P(a) = 1/2 ; P(b) = 1/3 and P(c) = 1/6

{a}        </span>→→→→1/2
<span>{b}        </span>→→→→1/3
<span>{c}        </span>→→→→1/6
<span>{a,b}     </span>→→→→1/2 + 1/3 =  5/6
<span>{a,c}     </span>→→→→1/2 + 1/6  =  2/3
<span>{b,c}     </span>→→→→1/3 + 1/6  =  1/2
<span>{a,b,c}  </span>→→→→1/2 + 1/3 + 1/6 = 1
<span>{∅}       </span>→→→→0 =0
5 0
3 years ago
Encrypt the word PLACE using an alphabetic Caesar shift cipher with shift 13 ( mapping A and N)​
Vladimir [108]
PLACE

P > C

L > Y

A > N

C > P

E > R

CYNPR
6 0
3 years ago
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