The lines have equal gradients;
m

Equation of line 2;
y=mx+c
y=

x+c
-15=

+c
c=-11
y=4/5x-11
Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:

Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:

Then your expression for this quadratic should be:

Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one
9514 1404 393
Answer:
7x +5y = -5
Step-by-step explanation:
You can find the perpendicular line by swapping the x- and y-coefficients, and negating one of them. The new constant can be found by using the given point.
7x +5y = 7(-5) +5(6) = -5
The perpendicular line through (-5, 6) is ...
7x +5y = -5
Answer: y= 0.96 + 0.18x
Step-by-step explanation: I just did the assignment
Answer:
-48r²-10r+3
Step-by-step explanation:
The answer would not be a negative 3 because -3×-1=3
Hope this helped!