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3 years ago

Please help me with number 2!!!!!!

Mathematics

2 answers:

anyanavicka [17]3 years ago

6 0

You just need to mirror it and move it slightly down

Snezhnost [94]3 years ago

3 0

Use Socratic it works good on apps stor if you can’t find it

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1/16^3x=64^2(x+8)<br> Solve for x.

SSSSS [86.1K]

Answer:

x = -4

Step-by-step explanation:

16 = 4*4 = 4²

64 = 4 * 4* 4 = 4³

$(\dfrac{1}{16})^{3x}=64^{2*(x+8)}\\\\\\(16^{-1})^{3x}=64^{2x + 16}\\\\\\16^{-3x}=64^{2x +16}\\\\(4^{2})^{-3x}=(4^{3})^{2x+16}\\\\4^{-6x}=4^{6x +48}$

As bases are same, compare exponents

6x + 48 = -6x

Subtract 48 from both sides

6x = -6x - 48

Add '6x' to both sides

6x + 6x = -48

12x = -48

Divide both sides by 12

x = -48/12

x = -4

3 0

2 years ago

Can you please help me with the whole table

Bad White [126]

44,000
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7 0

3 years ago

A meteor crater is 3000 feet in diameter. Approximate the distance around the crater use 3.14 for pi

Dima020 [189]

The distance around the crater is the circumference.

The formula for circumference is pi x diameter.

C= pi x d
C= 3.14 x 3000
C= 9420 feet

8 0

3 years ago

Find the gof of g[5X+2]^3-4

anygoal [31]

Answer:

what is value of f in given function

7 0

2 years ago

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

kogti [31]

Answer:

Advance tickets-$15

Same-day tickets-$20

Step-by-step explanation:

let x be the cost of advance tickets and y cost of same-day tickets:

$x+y=35\ \ \ \ \ \ \ ...i$

Given that there were 40 advance and 25 same-day tickets for a total of $1100:

$40x+25y=1100\\\\8x+5y=220\ \ \ \ \ \ \ \ \ \ \ ...ii$

#Make x the subject in i and substitute in ii:

$x=35-y\\\\\therefore 8x+5y=220, x=35-y\\\\8(35-y)+5y=220\\\\280-8y+5y=220\\\\60=3y\\\\y=20\\\\x=35-y=35-20=15$

Hence, advance tickets cost $15 each while same-day tickets cost $20 each.

5 0

3 years ago