$129.6
you do 100 times .08 and get 8 so 100 + 8 = 108
then you do 108 times .20 and get 21.6 so 108 + 21.6 = 129.6
Answer:
length of buyers driving record
Step-by-step explanation:
it just is because the driving record has nothing to do with monthly payments
answer:

Step-by-step explanation:
On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).
now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is
, where (p,q) is the turning point. now we substitute the turning point
, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.
0 = a(3.15 - 0.76)^2 + 57
-57 =a(2.39)^2
-57 = a(5.7121)
-57/5.7121 =a
-9.9788169 = a then we substitute a to get the quadratic equation therefore f is

Answer:
13/7
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(7-(-6))/(4-(-3))
m=(7+6)/(4+3)
m=13/7
This question does not make much sense. Brigid has already picked 112 bushels, and she picks at a rate of 58 bushels per hour, the scenario question does not make any sense. 58h + 112 = 5...? What does this mean? But whatever the left side of the equation is, first subtract 112 from both sides and divide by 58, then you will get the value of "h."