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oksian1 [2.3K]
3 years ago
8

2) Use a graph to find the length of DE if D(4, -3) and E(-5, -7).​

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

The answer rounded to the nearest tenth is 9.8.

Step-by-step explanation:

The answer itself is really long so I rounded to the tenths place.

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What is the simplest form of of this expression?
dangina [55]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Find the circumference of a circle whose area is 24
zalisa [80]

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________


The area, "A", of a circle:

A = \pi * r² ;

Note: \pi  = 3.14 .

The area of the circumference, "C", of a circle:

C = 2 \pi r .

__________________________________________

Given:

A = 24 ;

Use the formula for the area, "A" of a circle, to find the radius, "r" .

Then, plug the value obtained for "r" into the formula for the circumference, "C" , of a circle:

C = 2\pi r l

To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

24 = 3.14 * r² ;

↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

to isolate "r" on one side of the equation; & to solve for the radius, "r" ;

→ ⁺√(r²) = ⁺√(7.64331210191) ;

to get:

→ r = 2.76281034802 ;

____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

→ C = 2 \pi * r ;

to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________

6 0
3 years ago
Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the an
sergij07 [2.7K]

Answer:

D = 63.717

Step-by-step explanation:

The details that complete the question are:

(x_1,y_1) = (0,42.78)

and

(x_2,y_1)=(90,42.78)

Required

Determine how far the ball travelled

Distance is calculated using:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute values for x's and y's

D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}

D = \sqrt{42.78^2+(-47.22)^2

D = \sqrt{1830.1284+2229.7284

D = \sqrt{4059.8568

D = 63.717

<em>Hence, the ball travelled a distance of 63.717 units</em>

6 0
3 years ago
Please can anyone help me answer this question I'm really struggling with it
Anika [276]

Answer:

v =  {210cm}^{3}

Step-by-step explanation:

Formula for finding the volume of a triangular prism is given as:

v =  \frac{1}{2}  \times b \times h \times l

where,

b = breadth = 7cm

h = height = 6cm

l = length = 10cm

Thus,

v =  \frac{1}{2}  \times 7cm \times 6cm \times 10cm

v =  \frac{1}{2}  \times 420 {cm}^{3}

v  =  \frac{ {420cm}^{3} }{2}

v =  {210cm}^{3}

7 0
3 years ago
Lifetime of $1 Bills The average lifetime of circulated $1 bills is 18 months. A researcher believes that the average lifetime i
OLEGan [10]
<h2>Answer with explanation:</h2>

Let \mu be the population mean lifetime of circulated $1 bills.

By considering the given information , we have :-

H_0:\mu=18\\\\H_a:\mu\neq18

Since the alternative hypotheses is two tailed so the test is a two tailed test.

We assume that the lifetime of circulated $1 bills is normally distributed.

Given : Sample size :  n=50 , which is greater than 30 .

It means the sample is large so we use z-test.

Sample mean : \overline{x}=18.8

Standard deviation : \sigma=2.8

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{18.8-18}{\dfrac{2.8}{\sqrt{50}}}\approx2.02

The p-value= 2P(z>2.02)=0.0433834

Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.

6 0
3 years ago
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