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Anarel [89]
3 years ago
8

Determine whether the following statement regarding the hypothesistest for two population proportions is true or false.

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

False

Step-by-step explanation:

Let p1 be the population proportion for the first population

and p2 be the population proportion for the second population

Then

H_{0} p1  = p2

H_{a} p1 ≠ p2

Test statistic can be found usin the equation:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample population proportion for the first population
  • p2 is the sample population proportion for the second population
  • p is the pool proportion of p1 and p2
  • n1 is the sample size of the first population
  • n2 is the sample size of the second population.

As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.

As the<em> p-value</em> gets higher, the null hypothesis is less likely be rejected.

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(x, y) = (3, 1)

Step-by-step explanation:

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Answer:

Part 1) Australia 19,751,012\ people

Part 2) China 1,319,645,764\ people

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we know that

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a=19,169,000\\r=0.6\%=0.6\100=0.006

substitute

P(t)=19,169,000(1+0.006)^t

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Part 2) China

we have

a=1,261,832,000\\r=0.9\%=0.9\100=0.009

substitute

P(t)=1,261,832,000(1+0.009)^t

P(t)=1,261,832,000(1.009)^t

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Find the value of t

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P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people

Part 3) Mexico

we have

a=100,350,000\\r=1.8\%=1.8\100=0.018

substitute

P(t)=100,350,000(1+0.018)^t

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Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

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P(t)=51,965,000(1+0.031)^t

P(t)=51,965,000(1.031)^t

Find the  expected population in 2025,

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