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3 years ago

What is the length of ST

Mathematics

1 answer:

Zigmanuir [339]3 years ago

4 0

Take 4.95 and divide it into 2 and you will get ur answer of 2.475

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A radio arm saw has a circular cutting blade with a diameter of 10 inches and it spins at 2000rpm if there are 12 cutting teeth

FinnZ [79.3K]

Answer:

12565.11 teeth approximately cut cross the cutting surface per seconds.

Step-by-step explanation:

Since the diameter is 10inches, the circumference of the arm saw is 10π (circumference is πd where d is diameter).

The number of teeth on the cutting blade can be gotten by multiplying the diameter by 12 since we have 12 teeth per inch on the arm saw

Number of teeth on saw = 12 x 10π = 120π.

To get the number of teeth that cross the cutting surface in 2000rpm we multiple it by the total number of teeth in just one rpm.

So we have 2000 x 120π. But since we are asked to find it in revolution per seconds then 2000r/m = 2000r/60s ≈ 33.33

Therefore, we have

33.33 x 120π ≈ 12565.11 teeth

7 0

3 years ago

120% of 37 is what number?

xxMikexx [17]

120% of 37 is 44.4. Good luck!

4 0

3 years ago

Read 2 more answers

How many solutions does the equation have?

Andreyy89

Answer:

Since it is a linear equation, it has one solution.

step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

7) A baker had eighteen boxes for

Softa [21]

Answer:

Step-by-step explanation:

8 0

3 years ago