Answer:
the pic shows the coordinates
PLEASE HELP MEEEEEEE
1 answer:
You might be interested in
The standard form is:
Degree = 5, leading coefficient=4
The 5th degree polynomial is:
Quintic function
it is a trinomial
<u>What is standard form of a polynomial?</u>
When expressing a polynomial in its standard form, the greatest degree of terms are written first, followed by the next degree, and so on.
So, standard form is:
To find the degree of the polynomial, add up the exponents of each term and select the highest sum ( if there are more than 1 variable in single term) or highest power of variable
Degree = 5
In a polynomial, the leading term is the term with the highest power of x.
So, leading coefficient=4
The 5th degree polynomial is:
Quintic function
It has 3 terms. so, it is a trinomial
To learn more about the standard form of a polynomial from the given link
#SPJ1
9514 1404 393
Answer:
28 square units
Step-by-step explanation:
The rectangle is 7-0 = 7 units high and 6-2 = 4 units wide. Its area is the product of these dimensions:
A = LW
A = (7)(4) = 28 . . . square units
Answer:
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So
has a pvalue of 0.7881.
1 - 0.7881 = 0.2119
So 21.19% of the students use the computer for longer than 40 minutes.
Out of 10000
0.2119*10000 = 2119
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.