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3 years ago

Find the difference 7/x^2-3x - 1/x^2-9

1 answer:

6 0

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

<span>7/x^2-3x - 1/x^2-9
</span>
2. When you factor the denominator, you obtain:

<span>7/x(x-3) - 1/(x+3)(x-3)

3. By simplifying the expression, you obtain:

3(2x+7)/x(x+3)(x-3)
</span> 3(2x+7)/x(x^2-9)

The answer is: 3(2x+7)/x(x^2-9)

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How to write proofs in geometry

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3 years ago

What is the area of the yellow section?

nignag [31]

Answer:

98 $m^{2}$ i hope this helps! :)

Step-by-step explanation:

given 7 * 14 = ?

multiply 14 by 7 14 * 7 = 98

98 $m^{2}$

8 0

3 years ago

Read 2 more answers

give the answers to the remaining boxes left blank, you can give the answers all in one sentence starting from the first blank b

Thepotemich [5.8K]

The domain of the functions are:

The domain of f(x) = √4x + 6 is [-3/2, ∞) or x >-3/2
The domain of g(x) = -4√-20x - 6 is (-∞, -3/10] or x < -3/10
The domain of f(x) = 15 + √5x - 16 is [16/5, ∞) or x >16/5
The domain of p(x) = √20x + 6 is (-3/10, ∞] or x > -3/10

<h3>What are the domains of a function?</h3>

The domain of a function is the set of input values the function can take i.e. the set of values the independent variable can assume?

<h3>How to determine the domain of the functions?</h3>

<u>Function 1</u>

The function is given as:

f(x) = √4x + 6

Set the radicand greater than 0

4x + 6 > 0

Subtract 6 from both sides

4x > -6

Divide by 4

x > -3/2

Express as interval notation

[-3/2, ∞)

Hence, the domain of f(x) = √4x + 6 is [-3/2, ∞) or x >-3/2

<u>Function 2</u>

The function is given as:

g(x) = -4√-20x - 6

Set the radicand greater than 0

-20x - 6 > 0

Add 6 to both sides

-20x > 6

Divide by -20

x < -6/20

Simplify

x < -3/10

Express as interval notation

(-∞, -3/10]

Hence, the domain of g(x) = -4√-20x - 6 is (-∞, -3/10] or x < -3/10

<u>Function 3</u>

The function is given as:

f(x) = 15 + √5x - 16

Set the radicand greater than 0

5x - 16 > 0

Add 16 to both sides

5x > 16

Divide by 5

x > 16/5

Express as interval notation

[16/5, ∞)

Hence, the domain of f(x) = 15 + √5x - 16 is [16/5, ∞) or x >16/5

<u>Function 4</u>

The function is given as:

p(x) = √20x + 6

Set the radicand greater than 0

20x + 6 > 0

Subtract 6 from both sides

20x > -6

Divide by 20

x > -6/20

Simplify

x > -3/10

Express as interval notation

(-3/10, ∞]

Hence, the domain of p(x) = √20x + 6 is (-3/10, ∞] or x > -3/10