Find the difference 7/x^2-3x - 1/x^2-9
1 answer:
To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
<span>7/x^2-3x - 1/x^2-9
</span>
2. When you factor the denominator, you obtain:
<span>7/x(x-3) - 1/(x+3)(x-3)
3. By simplifying the expression, you obtain:
3(2x+7)/x(x+3)(x-3)
</span> 3(2x+7)/x(x^2-9)
The answer is: 3(2x+7)/x(x^2-9)
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Answer:
Step-by-step explanation:
D because it shows that 1x1/3 is shown on # D
46.19 should be the answer
(x,y)
x=input
y=output
example
we see
g=(1,2)
theefor
g(1)=2
a.
f(4)=1
g(1)=2
g(f(4))=2
b.
g(-2)=4
f(4)=1
f(g(-2))=1
c.
f(3)=5
g(5)=5
f(5)=0
f(g(f(3)))=0
