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miss Akunina [59]
4 years ago
12

Find the difference 7/x^2-3x - 1/x^2-9

Mathematics
1 answer:
Goshia [24]4 years ago
6 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following expression given in the problem above:

 <span>7/x^2-3x - 1/x^2-9
</span>
 2. When you factor the denominator, you obtain:

 <span>7/x(x-3) - 1/(x+3)(x-3)
 

 3. By simplifying the expression, you obtain:

 3(2x+7)/x(x+3)(x-3)
</span> 3(2x+7)/x(x^2-9)

 The answer is: 
 3(2x+7)/x(x^2-9)
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