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3 years ago

Find the difference 7/x^2-3x - 1/x^2-9

1 answer:

6 0

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

<span>7/x^2-3x - 1/x^2-9
</span>
2. When you factor the denominator, you obtain:

<span>7/x(x-3) - 1/(x+3)(x-3)

3. By simplifying the expression, you obtain:

3(2x+7)/x(x+3)(x-3)
</span> 3(2x+7)/x(x^2-9)

The answer is: 3(2x+7)/x(x^2-9)

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please only help with #3!

Alekssandra [29.7K]

Answer:

The polynomial is $x^{4}-4x^{3}+3x^{2}$

Step-by-step explanation:

∵ The polynomial of dgree 4 has 3 , 1 and zero as a double root

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∴ The factors of this polynomials are:

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3 years ago

What is the equation 28t = 1,232

sesenic [268]

Hello there!

To solve this equation, do 1232 ÷ 28 = 44
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3 years ago

Which of the following is equivalent to -12 + 3)?

natulia [17]

Answer:

$12 - 3$

Step-by-step explanation:

$( - 12 + 3) \\ = 12 - 3 \\ =- 9$

<h3>Hope it is helpful....</h3>

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3 years ago