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anzhelika [568]
3 years ago
14

The perimeter of a rectangular tray is 28 inches. The length of the tray is 2 inches longer the width of the tray. Determine the

dimensions of the rectangular tray.
Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

width = 6 and length = 8

Step-by-step explanation:

perimeter = 2*(length + width). (1)

and we have that length = 2 + width

in (1)

28 = 2 *(width + 2 + width)

14= 2*width +2

width =6

and so length will be 8

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Savatey [412]
It’s written in slope intercept form .
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3 years ago
Solve the equation<br> 12 + 4m = 24<br> A)m=9<br> B)m=8<br> C)m=3<br> D)m=-6
pantera1 [17]
12 +4m = 24

4m = 12

m = 12/4

m = 3  so choice C. is right sure 
8 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
The amount of tax for each camera is $5.25 and the tax rate is 6%. Explain how the equation: (Original Cost)(Percent) = Tax Amou
Degger [83]

x(1.06)=5.25

The reason it is 1.06 is because it is the original cost plus tax. You can divide each side by 1.06 to get x roughly equals 4.95.

So $4.95 is roughly what the camera costs rounded to the nearest cent.

3 0
4 years ago
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There are 7 coins that look identical.One of the seven coins weighs slightly less than the other 6. Using a balance scale, how c
RoseWind [281]
Start by putting two coins on each side of the scale. If one side is higher, then the light coin must be in that pair (use a second weighing to determine which of that pair is the lightest.)
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5 0
3 years ago
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