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3 years ago

Please help. Is algebra.

Mathematics

2 answers:

Stells [14]3 years ago

5 0

Answer:

I'm pretty sure the exponent of y is 2. so ?=2 hope this helps :D

Step-by-step explanation:

Vlad1618 [11]3 years ago

4 0

? = 2. Thats the only one i got that equals 8xy^2. Not sure if its right tho.

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2x + 3<br> 25°<br> S<br> Q<br> 3x – 170

Tpy6a [65]

Answer:

no idea what to find would you please like to explain about this question

6 0

3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

What is the following sum? 5(3sqrtx)+9(3sqrtx)

drek231 [11]

Answer:

5(3√x) +9(3√x) = 15√x+27√x= 42√x

5∛x + 9∛x = 14∛x

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is StartFraction 5 Over 8 EndFraction divided by One-fourth?

RideAnS [48]

Answer:

1/3

Step-by-step explanation:

8 0

3 years ago

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Please help I am confused.

nignag [31]

Answer:

9 cm, C

11 cm, B

14 cm A

Step-by-step explanation:

7 0

2 years ago