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3 years ago

9 1/2 gallons = how many quarts

2 answers:

6 0

There will be 38 quarts in a gallon because there are 4 quarts in a gallon, and 4 times 9 equals 36. Then, you have to add 2 because half a gallon is 2 and you get 38.

<u><em>*Hope I Helped*</em></u>

AysviL [449]3 years ago

4 0

Answer:

$9\frac{1}{2}$ gallons = 38 quarts.

Step-by-step explanation:

1 gallon = 4 quarts

Therefore, $9\frac{1}{2}$ gallons = $9\frac{1}{2}$ × 4

= $\frac{19}{2}$ × 4

= 38 quarts

$9\frac{1}{2}$ gallons = 38 quarts.

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Which of the following is a solution of y - x > -3?

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While there are no answers available to choose from, the correct pick would be any that has an x value that is less than 3 larger than the y value. For instance 1 and 3 would work.

y - x > -3
1 - 3 > -3
-2 > -3 (TRUE)

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4 years ago

Are these expressions equivalent 2(3x + 5) = 6x + 5?

Viktor [21]

Answer:

Step-by-step explanation:

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3 years ago

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ANTONII [103]

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3 years ago

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Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu

Tju [1.3M]

Answer:

a) 3.3352 inches.

b) 8.2648 inches.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 5.8, \sigma = 1.2$

A. What is the minimum head breadth that will fit the clientele?

This is the 2nd percentile, which is X when Z has a pvalue of 0.02. So X when Z = -2.054.

$Z = \frac{X - \mu}{\sigma}$

$-2.054 = \frac{X - 5.8}{1.2}$

$X - 5.8 = -2.054*1.2$

$X = 3.3352$

So the minimum head breadth that will fit the clientele is 3.3352 inches.

B. What is the maximum head breadth that will fit the clientele?

The 100-2 = 98th percentile, which is X when Z has a pvalue of 0.98. So X when Z = 2.054.

$Z = \frac{X - \mu}{\sigma}$

$2.054 = \frac{X - 5.8}{1.2}$

$X - 5.8 = 2.054*1.2$

$X = 8.2648$

So the maximum head breadth that will fit the clientele is 8.2648 inches.

8 0

4 years ago

The handford high school basketball team scored 79, 68, 86, 91 and 72 points in their first five games. What was the average num

Juli2301 [7.4K]

Answer: 79.2 points

Step-by-step explanation: The word "average" is the same as the word "mean" so to find the average of the points scored in their first 5 games, we want to add up all the points and divide them by the number of games they played which is 5 games.

Let's begin by adding the numbers.

79 + 68 + 86 + 91 + 72

Adding these numbers, we get a sum of 396.

This will be divided by how many games they played which is 5.

396 ÷ 5 = 79.2

This means that the average number of points scored is 79.2 points which could round down to 79 points but don't round unless the problem asks.

3 0

4 years ago